如何在python中将列表转换为数据框？

Question

所以，我有一个看起来像这样的列表：

      name=[["product 1",15,male,yes]
             ["product 2",10,female,yes]
             ["product 2",10,female,yes]
             ["product 3",none,female,yes]
             ["product 4",20,yes,male]]
     and so on...

我希望使用类函数来获得这样的结果：

 [Item("product 1",15,"male","yes"), 
  Item("product 2",10,"female", "yes"), 
  Item("product 2",10,"female", "yes"), 
  Item("product 3",none,"female","no"), 
  Item('product 4",20,"male","yes")...so on]

接下来我希望删除缺少元素的部分：

[Item("product 1",15,"male","yes"), 
 Item("product 2",10,"female", "yes"), 
 Item("product 2",10,"female", "yes"), 
 Item('product 4",20,"male","yes")...so on]

对于产品 4，订单已更改。还有一些像产品 4 一样的产品，也是乱序的（它们乱序的方式也不同。）

我已经为“上课”做了一些准备，但我不知道在这里做什么：

class Item():
__name = ""
__cost = 0
__gender = ""
__prime = ""

def __init__(self, name, cost, gender, prime):
    self.__name = name
    self.__cost = cost
    self.__gender = gender
    self.__prime = prime

任何人都可以展示 Python 代码来做到这一点吗？提前谢谢你。

Answer 1

答案很明显，不是吗？我认为你让事情变得更难了。

timr@tims-gram:~/src$ cat x.py
name=[
    ["product 1",15,"male","yes"],
    ["product 2",10,"female","yes"],
    ["product 2",10,"female","yes"],
    ["product 3",None,"female","yes"],
    ["product 4",20,"male","yes"]
]

class Item():
    _name = ""
    _cost = 0
    _gender = ""
    _prime = ""

    def __init__(self, name, cost, gender, prime):
        self._name = name
        self._cost = cost
        self._gender = gender
        self._prime = prime

    def __repr__(self):
        return f"Item({self._name},{self._cost},{self._gender},{self._prime})"

mylist = [Item(*k) for k in name if k[1]]
print(mylist)

输出：

timr@tims-gram:~/src$ python x.py
[Item(product 1,15,male,yes), Item(product 2,10,female,yes), Item(product 2,10,female,yes), Item(product 4,20,male,yes)]
timr@tims-gram:~/src$