Python 3 - 从字典列表中随机打印项目而不重复

Question

我有一些我在测验中使用的代码的修改版本，我的问题是我的代码正在使用 random.choice 来选择一个测验问题，我如何让它仍然随机选择一个问题但也不重复一个问题已经向用户询问过？

对“quiz_data”中奇怪的问题和答案表示歉意

代码：

def InformationToDictionaries():
quiz_data = [
    {
        "question": "What day is it today?",
        "choices": {"a": "Monday", "b": "Friday", "c": "Wednesday", "d": "Sunday"},
        "answer": "Wednesday")
    },
    {
        "question": "What food am I thinking of?",
        "choices": "Pizza", "b": "Curry", "c": "Pie", "d": "Pasta"},
        "answer": "Curry"
    }
]
return quiz_data


def Quiz():
    score = 0
    for i in range(1,6):
        q = random.choice(quiz_data)
        print("Q." + str(i) + ": ", q.get("question"))
        print('\n'.join("{}: {}".format(x, y) for x, y in q.get("choices").items()))
        userans = str(input("\n>"))

    if userans == q.get("answer"):
        print("Correct")
        score = score + 1
    else: print("Incorrect")

quiz_data = InformationToDictionaries()
Quiz()

非常感谢您提前回复，如果您对我有任何建议，请告诉我，这是我的第一个问题。

--------编辑1---------

第一次建议后修改代码：

def Quiz():
score = 0
random.shuffle(quiz_data)
for question in quiz_data:
    q = random.choice(quiz_data)
    print("Q." + str("1") + ": ", q.get("question"))
    print('\n'.join("{}: {}".format(x, y) for x, y in q.get("choices").items()))

Answer 1

有几种方法。就像在使用后从列表中删除问题一样，或者随机排列数组并遍历它。

要在每次选择问题时从数组中删除所有问题：

while(len(quiz_data) != 0):
  q = random.choice(quiz_data)
  quiz_data.remove(q)
  #do stuff with q

如果你想遍历一个打乱的数组：

from random import shuffle
shuffle(quiz_data)
for question in quiz_data:
  pass #this is only here for the code to run
  #do stuff with question

这两种方式都会以随机顺序为您提供所有问题

Answer 2

在您修改后的代码中，您仍在循环中选择一个随机问题。如果你去掉 q = random.choice(quiz_data) 行并在循环体中使用 question 变量，你可以按照打乱的顺序来处理它们。

score = 0
random.shuffle(quiz_data)
for question in quiz_data:
    print("Q." + str("1") + ": ", question.get("question"))
    print('\n'.join("{}: {}".format(x, y) for x, y in question.get("choices").items()))