计算每个字母在文本样本中出现的次数

Question

我需要一个函数来计算每个字母在字符串中出现的次数。它必须将大写和小写视为同一个字母。我有点做到了，但它并不完全漂亮。

def lmao(x):

    aye=x.count("a")
    Aye=x.count("A")
    bye=x.count("b")
    Bye=x.count("B")
    cye=x.count("c")
    Cye=x.count("C")
    dye=x.count("d")
    Dye=x.count("D")
    Eye=x.count("E")
    eye=x.count("e")
    Fye=x.count("F")
    fye=x.count("f")
    Gye=x.count("G")
    gye=x.count("g")
    Hye=x.count("H")
    hye=x.count("h")
    Iye=x.count("I")
    iye=x.count("i")
    Jye=x.count("J")
    jye=x.count("j")
    Kye=x.count("K")
    kye=x.count("k")
    Lye=x.count("L")
    lye=x.count("l")
    Mye=x.count("M")
    mye=x.count("m")
    Nye=x.count("N")
    nye=x.count("n")
    Oye=x.count("O")
    oye=x.count("o")
    Pye=x.count("P")
    pye=x.count("P")
    Qye=x.count("Q")
    qye=x.count("q")
    rye=x.count("r")
    Rye=x.count("R")
    sye=x.count("s")
    Sye=x.count("S")
    tye=x.count("t")
    Tye=x.count("T")
    uye=x.count("u")
    Uye=x.count("U")
    Vye=x.count("V")
    vye=x.count("v")
    Wye=x.count("W")
    wye=x.count("w")
    Xye=x.count("X")
    xye=x.count("x")
    Yye=x.count("Y")
    yye=x.count("y")
    Zye=x.count("Z")
    zye=x.count("z")
    killme=(aye+Aye,bye+Bye,cye+Cye,Dye+dye,Eye+eye,Fye+fye,Gye+gye,Hye+hye,Iye+iye,jye+Jye,Kye+kye,Lye+lye,Mye+mye,Nye+nye,Oye+oye,Pye+pye,Qye+qye,rye+Rye,sye+Sye,Tye+tye,uye+Uye,Vye+vye,Wye+wye,xye+Xye,Yye+yye,Zye+zye)
    return killme

所以是的，这就是我想出的灾难。有什么办法可以缩短这个过程？

Answer 1

使用collections.Counterhttps://docs.python.org/2/library/collections.html#counter-objects

from collections import Counter    
counter = Counter(mystr.lower())

会给你每个字母的所有出现，忽略大小写

Answer 2

这可能会有所帮助：

def counter(text):
    count_list = []
    for char in "abcdefghijklmnopqrstuvwxyz":
        count_list.append(text.lower().count(char))
    return tuple(count_list)

print(counter("Helllo123"))

输出：

(0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 3, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0)

Answer 3

准确返回您的要求：

import string
def lmao(x):
    return tuple(x.lower().count(c) for c in string.lowercase)

Answer 4

使用 counter 和字典理解来获取每个字母的计数。

import string
from collections import Counter

对于一个 alpha 排序的元组，

def count_letter_tuples(sentence):
    return tuple(Counter(sentence.lower()).get(c, 0) for c in string.ascii_lowercase)

>>> count_letter_tuples("Some Big Sentence")
(0, 0, 1, 0, 4, 0, 1, 0, 1, 0, 0, 0, 1, 2, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0)

或者对于字典响应：

def count_letters(sentence):
    return {c: Counter(sentence.lower()).get(c, 0) for c in string.ascii_lowercase}

>>> count_letters("Some Big Sentence")
{'a': 0,
 'b': 1,
 'c': 1,
 'd': 0,
 'e': 4,
 'f': 0,
 'g': 1,
 'h': 0,
 'i': 1,
 'j': 0,
 'k': 0,
 'l': 0,
 'm': 1,
 'n': 2,
 'o': 1,
 'p': 0,
 'q': 0,
 'r': 0,
 's': 2,
 't': 1,
 'u': 0,
 'v': 0,
 'w': 0,
 'x': 0,
 'y': 0,
 'z': 0}