如何将文件传递给处理文件夹的脚本

Question

所以我有这个 bash 脚本，它将重命名当前目录中的所有文件。我需要帮助来修改它，这样我就可以只指定某些将被重命名的文件，但仍然可以将它传递给一个目录。我对 bash 不是很熟悉，所以这让我很困惑。

#!/bin/bash

#
# Filename: rename.sh
# Description: Renames files and folders to lowercase recursively
#              from the current directory
# Variables: Source = x
#            Destination = y

#
# Rename all directories. This will need to be done first.
#

# Process each directory’s contents before the directory  itself
for x in `find * -depth -type d`;
do

  # Translate Caps to Small letters
  y=$(echo $x | tr '[A-Z]' '[a-z]');

  # check if directory exits
  if [ ! -d $y ]; then
    mkdir -p $y;
  fi

  # check if the source and destination is the same
  if [ "$x" != "$y" ]; then

    # check if there are files in the directory
    # before moving it
    if [ $(ls "$x") ]; then
      mv $x/* $y;
    fi
    rmdir $x;

  fi

done

#
# Rename all files
#
for x in `find * -type f`;
do
  # Translate Caps to Small letters
  y=$(echo $x | tr '[A-Z]' '[a-z]');
  if [ "$x" != "$y" ]; then
    mv $x $y;
  fi
done

exit 0

Answer 1

您的脚本有大量初学者错误，但标题中的实际问题有一些优点。

对于这样的任务，我会选择递归解决方案。

tolower () {
    local f g
    for f; do
        # If this is a directory, process its contents first
        if [ -d "$f" ]; then
            # Recurse -- run the same function over directory entries
            tolower "$f"/*
        fi
        # Convert file name to lower case (Bash 4+)
        g=${f,,}
        # If lowercased version differs from original, move it
        if [ "${f##*/}" != "${g##*/}" ]; then
            mv "$f" "$g"
        fi
    done
}

注意包含文件名的变量如何总是被引用（否则，您的脚本将在包含 shell 元字符的文件名上失败）以及 Bash 如何具有 built-in functionality for lowercasing a variable's value（最近版本）。

另外，切线，don't use ls in scripts 并在寻求人工调试帮助之前尝试http://shellcheck.net/。