ASP.NET Web API 2：ExceptionLogger 和异常处理程序答案

【问题标题】：ASP.NET Web API 2: ExceptionLogger and Exception HandlerASP.NET Web API 2：ExceptionLogger 和异常处理程序
【发布时间】：2017-02-01 11:06:57
【问题描述】：

我正在尝试在 web api 中实现全局异常日志记录，并向具有该错误 ID 的用户发送一条友好的消息，以便他可以返回给我们错误 ID，以便我们修复它。我正在实现这两个：

System.Web.Http.ExceptionHandling.ExceptionLogger
System.Web.Http.ExceptionHandling.ExceptionHandler

这是我的覆盖 ExceptionLogger 抽象类的类：

public class GlobalExceptionLogger : System.Web.Http.ExceptionHandling.ExceptionLogger
{
    public override void Log(ExceptionLoggerContext context)
    {
        LogMessage logMsg = new LogMessage();
        logMsg.ID = System.Guid.NewGuid().ToString();
        logMsg.MessageType = MessageType.ResourceServerAPI;
        logMsg.SenderMethod = context.Request.RequestUri != null ? string.Format("Request URL: {0}", context.Request.RequestUri.ToString()) : "";
        logMsg.Level = MesageLevel.Error;
        logMsg.MachineName = Environment.MachineName;
        logMsg.Message = context.Exception.Message;

        Logger.LogError(logMsg);
    }
}

这是我处理错误的方式：

public class GlobalExceptionHandler : System.Web.Http.ExceptionHandling.ExceptionHandler
{
    public override void Handle(ExceptionHandlerContext context)
    {
        var metadata = new ErrorData
        {
            Message = "An error occurred! Please use the ticket ID to contact our support",
            DateTime = DateTime.Now,
            RequestUri = context.Request.RequestUri,
            ErrorId = //get the ID already logged
        };

        var response = context.Request.CreateResponse(HttpStatusCode.InternalServerError, metadata);
        context.Result = new ResponseMessageResult(response);        
    }
}

由于异常记录发生在处理之前，将 ID 从 Exception Logger 传递到 Exception Handler 以向最终用户发送相应的错误 Id 的最佳方法是什么？

【问题讨论】：

标签： c# error-handling exception-handling asp.net-web-api2

【解决方案1】：

你可以添加到HttpRequestMessage.Properties:

public static class HttpRequestMessageExtensions
{
    private const string LogId = "LOG_ID";

    public static void SetLogId(this HttpRequestMessage request, Guid id)
    {
        request.Properties[LogId] = id;
    }

    public static Guid GetLogId(this HttpRequestMessage request)
    {
        object value;
        if (request.Properties.TryGetValue(LogId, out value))
        {
            return (Guid) value;
        }

        return Guid.Empty;
    }
}

然后在您的记录器/处理程序中使用这些扩展方法：

public class GlobalExceptionLogger : System.Web.Http.ExceptionHandling.ExceptionLogger
{
    public override void Log(ExceptionLoggerContext context)
    {
        LogMessage logMsg = new LogMessage();
        logMsg.ID = System.Guid.NewGuid().ToString();
        logMsg.MessageType = MessageType.ResourceServerAPI;
        logMsg.SenderMethod = context.Request.RequestUri != null ? string.Format("Request URL: {0}", context.Request.RequestUri.ToString()) : "";
        logMsg.Level = MesageLevel.Error;
        logMsg.MachineName = Environment.MachineName;
        logMsg.Message = context.Exception.Message;

        // Set the ID
        context.Request.SetLogId(logMsg.ID);

        Logger.LogError(logMsg);
    }
}

public class GlobalExceptionHandler : System.Web.Http.ExceptionHandling.ExceptionHandler
{
    public override void Handle(ExceptionHandlerContext context)
    {
        // Get the ID
        var id = context.Request.GetLogId();

        var metadata = new ErrorData
        {
            Message = "An error occurred! Please use the ticket ID to contact our support",
            DateTime = DateTime.Now,
            RequestUri = context.Request.RequestUri,
            ErrorId = id

        };

        var response = context.Request.CreateResponse(HttpStatusCode.InternalServerError, metadata);
        context.Result = new ResponseMessageResult(response);
    }
}

【讨论】：