【发布时间】:2020-08-12 15:59:51
【问题描述】:
当我尝试将 1.1 之类的数字转换为双精度时,我得到一个异常:“输入字符串的格式不正确。”我不知道为什么会这样,因为我给出的输入是正确的,而我要转换的变量是双精度的。下面是代码:
控制器创建方法:
[ValidateAntiForgeryToken]
public ActionResult Create(IFormCollection collection)
{
try
{
Riskanalysis riskanalysis = new Riskanalysis()
{
dateCreation = Convert.ToDateTime(collection["dateCreation"]),
userId = collection["userId"],
categoryId = Convert.ToInt32(collection["categoryId"]),
zoneId = Convert.ToInt32(collection["zoneId"]),
equipmentId = Convert.ToInt32(collection["equipmentId"]),
taskId = Convert.ToInt32(collection["taskId"]),
activity = collection["activity"],
action = collection["action"],
descriptionPotentialRisk = collection["descriptionPotentialRisk"],
dangerId = Convert.ToInt32(collection["dangerId"]),
consequenceId = Convert.ToInt32(collection["consequenceId"]),
dangerousEnergiesId = Convert.ToInt32(collection["dangerousEnergiesId"]),
preventionMeasures = collection["preventionMeasures"],
safetyProcedures = collection["safetyProcedures"],
preSeriousness = Convert.ToDouble(collection["preSeriousness"]),
preProbability = Convert.ToDouble(collection["preProbability"]),
preExposure = Convert.ToDouble(collection["preExposure"]),
preRiskDegree = Convert.ToDouble(collection["preRiskDegree"]),
preRiskCategory = Convert.ToDouble(collection["preRiskCategory"]),
};
DanoneRiskanalysisManager rm = new DanoneRiskanalysisManager();
rm.InsertRiskanalysis(riskanalysis);
return RedirectToAction(nameof(Create));
}
catch (Exception e)
{
return View();
}
}
输入字段:
<div class="form-group">
<label asp-for="preSeriousness" class="control-label">Pre seriousness:</label>
<input asp-for="preSeriousness" class="form-control" type="text" required/>
<span asp-validation-for="preSeriousness" class="text-danger"></span>
</div>
<div class="form-group">
<label asp-for="preProbability" class="control-label">Pre probability:</label>
<input asp-for="preProbability" class="form-control" type="text" required/>
<span asp-validation-for="preProbability" class="text-danger"></span>
</div>
<div class="form-group">
<label asp-for="preExposure" class="control-label">Pre exposure:</label>
<input asp-for="preExposure" class="form-control" type="text" required/>
<span asp-validation-for="preExposure" class="text-danger"></span>
</div>
<div class="form-group">
<label asp-for="preRiskDegree" class="control-label">Pre risk degree:</label>
<input asp-for="preRiskDegree" class="form-control" type="text" required/>
<span asp-validation-for="preRiskDegree" class="text-danger"></span>
</div>
<div class="form-group">
<label asp-for="preRiskCategory" class="control-label">Pre risk category:</label>
<input asp-for="preRiskCategory" class="form-control" type="text" required/>
<span asp-validation-for="preRiskCategory" class="text-danger"></span>
</div>
任何人都知道可能是什么原因或在哪里寻找?
已经谢谢了!
【问题讨论】:
-
你检查过区域设置了吗?,可能数字格式不使用“。”作为小数分隔符,请尝试输入“,”而不是“。”
-
这解决了它,非常感谢!可能是因为我住在比利时,他们使用“,”而不是“。”?
-
很高兴听到语言环境
CultureInfo.InvariantCulture在这种情况下可以帮助您。此外,在解析像您这样的对象类型时,我也遇到了类似的错误,并且由于集合较大,几乎难以跟踪。当然,我建议在需要时使用Double.TryParse。 -
@henocsalinas 您应该将其作为答案,AVandijck 会将其标记为正确答案
-
是的,我正在考虑使用 Double.TryParse,但是我必须为每个输入创建一个 int 变量还是我弄错了?
标签: c# asp.net-mvc string exception double