使用 Python 模块在文件上打开资源管理器

Question

我是 python 新手，我在使用位于 Open explorer on a file 的一些非常有用的代码制作模块时遇到了一些困难。

我不知道我做错了什么。

我收到以下错误消息：

第 31 行：C:\Apps\E_drive\Python_win32Clipboard.pdf 第 34 行：r'explorer /select, "C:\Apps\E_drive\Python_win32Clipboard.pdf"' Traceback (大多数 最近通话最后）：文件 "P:\Data\VB\Python_MarcsPrgs\Python_ItWorks\Open_Win_Explorer_and_Select_File.py", 第 42 行，在 Open_Win_Explorer_and_Select_Fil（文件路径）文件“P:\Data\VB\Python_MarcsPrgs\Python_ItWorks\Open_Win_Explorer_and_Select_File.py”， 第 35 行，在 Open_Win_Explorer_and_Select_Fil subprocess.Popen(Popen_arg) 文件“C:\Python27\lib\subprocess.py”，第 679 行，在 init errread, errwrite) 文件“C:\Python27\lib\subprocess.py”，第 893 行，在 _execute_child startupinfo) WindowsError: [错误 2] 系统找不到指定的文件

这是我的模块：

"""
Open Win Explorer and Select File
# "C:\Apps\E_drive\Python_win32Clipboard.pdf"
"""
import sys
import os, subprocess, pdb

def fn_get_txt_sysarg():
    "Harvest a single (the only) command line argument"
    # pdb.set_trace()
    try:
        arg_from_cmdline = sys.argv[1]
        arg_from_cmdline = str(arg_from_cmdline)

    except:
        this_scriptz_FULLName = sys.argv[0]

        ErrorMsg = "Message from fn_get_txt_sysarg() in Script (" + this_scriptz_FULLName + '):\n' \
        + "\tThe Script did not receive a command line argument (arg_from_cmdline)"

    returnval = arg_from_cmdline

    return returnval


def Open_Win_Explorer_and_Select_Fil(filepathe):
    # harvested from... https://stackoverflow.com/questions/281888/open-explorer-on-a-file
    #import subprocess 
    #subprocess.Popen(r'explorer /select,"C:\path\of\folder\file"') 
    f = str(filepathe)
    print "line 31: " + f
    Popen_arg = "r'explorer /select, " + '"' + f + '"' + "'"
    Popen_arg = str(Popen_arg)
    print "line 34: " + Popen_arg
    subprocess.Popen(Popen_arg)


if __name__ == '__main__': 

    filepath = fn_get_txt_sysarg()

    Open_Win_Explorer_and_Select_Fil(filepath)    

任何帮助将不胜感激。

             Marceepoo

Answer 1

我复制了您的代码并在我的机器上运行它，发现两个错误。 answer srgerg provided 解决了这些错误之一。另一种是当命令行没有指定参数时，Python 会在 fn_get_txt_sysarg() 中触发错误。下面是一些示例代码，修复了错误并进行了一些其他清理工作：

"""
Open Win Explorer and Select File
"""
import sys
import subprocess

def fn_get_txt_sysarg():
    """Harvest a single (the only expected) command line argument"""
    try:
        return sys.argv[1]    # str() would be redundant here
    except:
        ErrorMsg = 'Message from fn_get_txt_sysarg() in Script (' + sys.argv[0] + '):\n' + '\tThe Script did not receive a command line argument'
        sys.exit(ErrorMsg)

def Open_Win_Explorer_and_Select_Fil(filepath):
    # harvested from: https://stackoverflow.com/questions/281888/open-explorer-on-a-file
    Popen_arg = 'explorer /select,"' + filepath + "'"    # str() is redundant here also
    subprocess.Popen(Popen_arg)

if __name__ == '__main__': 
    filepath = fn_get_txt_sysarg()
    Open_Win_Explorer_and_Select_Fil(filepath)

Answer 2

我认为问题在于Popen_arg 的初始化。请注意，Popen_arg 的输出值为：

r'explorer /select, "C:\Apps\E_drive\Python_win32Clipboard.pdf"'

这实际上是一个pythonraw string literal。您希望 Popen_arg 具有此字符串文字所代表的值，而不是此字符串文字本身。我想如果你把它改成

Popen_arg = r'explorer /select, "' + f + '"'

效果会更好。还要注意这一行：

Popen_arg = str(Popen_arg)

没有效果，可以安全移除。