【发布时间】:2018-03-26 09:35:16
【问题描述】:
我目前在使用 Python 2.7 生成具有多行文本的文本文件并将其添加到内存中的 ZipFile 方面遇到一些困难。
下面的代码可以生成包含 4 个文本文件的 zip 文件,每个文件有 1 行单词。
如果我将代码“temp[0].write('first in-memory temp file')”修改为多行字符串,生成的zip文件会出现crc错误。
我尝试过字符串转义,但失败了。
我可以知道我应该怎么做才能生成填充多行启用文本文件的 ZipFile 吗?
提前致谢。
# coding: utf-8
import StringIO
import zipfile
# This is where my zip will be written
buff = StringIO.StringIO()
# This is my zip file
zip_archive = zipfile.ZipFile(buff, mode='w')
temp = []
for i in range(4):
# One 'memory file' for each file
# I want in my zip archive
temp.append(StringIO.StringIO())
# Writing something to the files, to be able to
# distinguish them
temp[0].write('first in-memory temp file')
temp[1].write('second in-memory temp file')
temp[2].write('third in-memory temp file')
temp[3].write('fourth in-memory temp file')
for i in range(4):
# The zipfile module provide the 'writestr' method.
# First argument is the name you want for the file
# inside your zip, the second argument is the content
# of the file, in string format. StringIO provides
# you with the 'getvalue' method to give you the full
# content as a string
zip_archive.writestr('temp'+str(i)+'.txt',
temp[i].getvalue())
# Here you finish editing your zip. Now all the information is
# in your buff StringIO object
zip_archive.close()
# You can visualize the structure of the zip with this command
print zip_archive.printdir()
# You can also save the file to disk to check if the method works
with open('test.zip', 'w') as f:
f.write(buff.getvalue())
【问题讨论】:
标签: python python-2.7 text-files zipfile stringio