如何从 shell 脚本执行终端命令？ (MacOS 10.12)

Question

我正在编写一段 shell 脚本代码，以便在我的 Mac 上自动执行一组终端任务。该程序在 Mac 终端中执行，但是当任何 if 语句为真时，if 语句中的嵌套命令不会执行。有什么建议吗？

#!/bin/bash

FINDER="1"
DOCK="2"
CAFF="3"

echo Select an option:
echo 1. killall Finder
echo 2. killall Dock
echo 3. caffeinate

echo Enter you choice:
read CHOICE

if [ "$CHOICE"="$FINDER" ]; then
    killall Finder
elif [ "$CHOICE"="$DOCK" ]; then
    killall Dock
elif [ "$CHOICE"="$CAFF" ]; then
    caffeinate
fi

exit

Answer 1

感谢这个论坛的帮助，我能够解决这个问题。这是现在可以工作的代码块：

#!/bin/bash

CHOICE=0
FINDER=1
DOCK=2
CAFF=3

echo Select an option:
echo 1. killall Finder
echo 2. killall Dock
echo 3. caffeinate

echo -n Enter your choice:
read CHOICE

echo You chose: $CHOICE

if [ $CHOICE = $FINDER ]; then
    echo Executing killall Finder…
    killall Finder
elif [ $CHOICE = $DOCK ]; then
    echo Executing killall Dock…    
    killall Dock
elif [ $CHOICE = $CAFF ]; then
    echo Executing caffeinate…
    caffeinate
fi

exit

Answer 2

条件中等号周围缺少空格。

#!/bin/bash

FINDER="1"
DOCK="2"
CAFF="3"

echo Select an option:
echo 1. killall Finder
echo 2. killall Dock
echo 3. caffeinate

echo Enter you choice:
read CHOICE

if [ "$CHOICE" = "$FINDER" ]; then
    killall Finder
elif [ "$CHOICE" = "$DOCK" ]; then
    killall Dock
elif [ "$CHOICE" = "$CAFF" ]; then
    caffeinate
fi