如何在连接中将dict转换为字符串？

Question

我有一个由 API 调用生成的 Python 字典类，返回结果如下

{'url': 'https://propertypro.zendesk.com/api/v2/tickets/4249.json', 'id': 4249, 'external_id'：无}

{'url': 'https://propertypro.zendesk.com/api/v2/tickets/4089.json', 'id': 4089, 'external_id'：无}

代码如下；

from urllib.parse import urlencode

import requests

credentials = 'some email', 'some password'
session = requests.Session()
session.auth = credentials

params = {
    'query': 'type:ticket tags:test_python',
    'sort_order': 'asc'
}

url = 'https://propertypro.zendesk.com/api/v2/search.json?' + urlencode(params)
response = session.get(url)
if response.status_code != 200:
    print('Status:', response.status_code,
          'Problem with the request. Exiting.')
    exit()

# Print the subject of each ticket in the results
data = response.json()

我迭代数据以获取键“id”中的所有值，以用逗号分隔的字符串分配给变量id_merged

for result in data['results']:
    # Ticket to update
    id_merged = (result['id'])

但只得到一个结果而不是 2，var 在循环中被覆盖？

from test_search import data
import json
import requests

# Iterate the search result
for result in data['results']:
    # Ticket to update
    id_merged = (result['id'])

print("**Start**")
print(id)
body = 'Test ticket'

# Package the data in a dictionary matching the expected JSON
data_comment = {'ticket': {'comment': {'body': body}}}

# Encode the data to create a JSON payload
payload = json.dumps(data_comment)

# Set the request parameters
url = 'https://propertypro.zendesk.com/api/v2/tickets/update_many.json?' + \
    'ids=' + str(id_merged)
user = 'some email'
pwd = 'some password'
headers = {'content-type': 'application/json'}

# Do the HTTP put request
response = requests.put(url, data=payload,
                        auth=(user, pwd), headers=headers)

# Check for HTTP codes other than 200
if response.status_code != 200:
    print('Status:', response.status_code,
          'Problem with the request. Exiting.')
    exit()

# Report success
print('Successfully added comment to ticket #{}'.format(id))

我想得到类似 'https://propertypro.zendesk.com/api/v2/tickets/update_many.json?' + \ 'ids=' + 4249,4089 的结果。

我如何得到这个？

Answer 1

看起来您正在获取 dict 值中的列表列表，在这种情况下，您可以展平列表并加入字符串“，”，例如：

>>> import itertools
>>> ",".join(map(str, list(itertools.chain(*[[1,2,3],[4,5]]))))
'1,2,3,4,5'

Answer 2

如果要将id 的值转换为逗号分隔的字符串，可以执行以下操作。

','.join(id.values())

所以把你的代码改成

url = 'str,' + 'str1:' + ','.join(id.values())

为了完整起见，如果您想对字典键做同样的事情，您只需使用

','.join(id)