【发布时间】：2019-03-04 16:43:42
【问题描述】：
我在 R 中有 2 个列表，列表名称如下：
str(total_delta_final[[1]])
List of 4
$ sector1_T02 :'data.frame': 24 obs. of 3 variables:
..$ DeltaF_1: num [1:24] 0.737 0.737 0.693 0.738 0.738 ...
..$ DeltaF_2: num [1:24] 0.24 0.24 0.279 0.239 0.239 ...
..$ DeltaF_3: num [1:24] 0.0233 0.0233 0.0275 0.0232 0.0232 ...
$ sector2_T03 :'data.frame': 24 obs. of 3 variables:
..$ DeltaF_1: num [1:24] 0.582 0.582 0.568 0.69 0.69 ...
..$ DeltaF_2: num [1:24] 0.377 0.377 0.39 0.282 0.282 ...
..$ DeltaF_3: num [1:24] 0.0406 0.0406 0.0426 0.0278 0.0278 ...
$ sector3_T03 :'data.frame': 24 obs. of 3 variables:
..$ DeltaF_1: num [1:24] 0.607 0.607 0.495 0.409 0.375 ...
..$ DeltaF_2: num [1:24] 0.356 0.356 0.451 0.519 0.544 ...
..$ DeltaF_3: num [1:24] 0.0373 0.0373 0.0541 0.072 0.0809 ...
$ sector12_T02:'data.frame': 24 obs. of 3 variables:
..$ DeltaF_1: num [1:24] 0.743 0.743 0.758 0.689 0.705 ...
..$ DeltaF_2: num [1:24] 0.234 0.234 0.22 0.283 0.269 ...
..$ DeltaF_3: num [1:24] 0.0226 0.0226 0.0213 0.028 0.0263 ...
> str(total_TI_final[[1]])
List of 4
$ sector1_T02 :'data.frame': 24 obs. of 3 variables:
..$ I_1: num [1:24] NA 0.0756 0.083 0.0799 0.0799 ...
..$ I_2: num [1:24] 0.122 NA 0.163 0.172 0.172 ...
..$ I_3: num [1:24] 0.212 0.211 NA 0.266 0.273 ...
$ sector2_T03 :'data.frame': 24 obs. of 3 variables:
..$ I_1: num [1:24] NA 0.0986 0.1013 0.1011 0.101 ...
..$ I_2: num [1:24] 0.15 NA 0.184 0.211 0.211 ...
..$ I_3: num [1:24] 0.249 0.249 NA 0.331 0.337 ...
$ sector3_T03 :'data.frame': 24 obs. of 3 variables:
..$ I_1: num [1:24] NA 0.119 0.115 0.113 0.105 ...
..$ I_2: num [1:24] 0.193 NA 0.2 0.193 0.177 ...
..$ I_3: num [1:24] 0.323 0.323 NA 0.277 0.256 ...
$ sector12_T02:'data.frame': 24 obs. of 3 variables:
..$ I_1: num [1:24] NA 0.0825 0.0681 0.0723 0.0706 ...
..$ I_2: num [1:24] 0.138 NA 0.146 0.145 0.144 ...
..$ I_3: num [1:24] 0.24 0.24 NA 0.22 0.226 ...
如何合并这两个列表列表，使我的最终输出看起来像 total_TI_final[[1]][1] 和第二个列表 total_delta_final[[1]][1] 然后 total_TI_final[[1]][2] 和 total_delta_final[[1]][2] 等等...
【问题讨论】：