【发布时间】:2021-10-24 19:09:37
【问题描述】:
我在表单中有两个数据框:
数据框(df1):
| P_CLIENT_ID | P_DATE_ENCOUNTER |
|---|---|
| 25835 | 2016-12-21 |
| 25835 | 2017-02-21 |
| 25835 | 2017-04-25 |
| 25835 | 2017-06-21 |
| 25835 | 2017-09-04 |
| 25835 | 2018-01-08 |
| 25835 | 2018-04-03 |
数据框(df2):
| R_CLIENT_ID | R_DATE_TESTED | R_RESULT |
|---|---|---|
| 25835 | 2017-03-07 | 20.0 |
| 25835 | 2017-08-03 | 20.0 |
| 25835 | 2018-03-23 | 20.0 |
| 25835 | 2019-06-28 | 20.0 |
| 25835 | 2019-08-19 | 42.0 |
| 25835 | 2020-04-20 | 40.0 |
| 25835 | 2021-06-03 | 20.0 |
我想将 df2 合并到 df1(主表),连接键为 P_CLIENT_ID 和 R_CLIENT_ID 附加最新的 R_DATE_TESTED 和 R_RESULT
第一个条件:
如果 R_DATE_TESTED > P_DATE_ENCOUNTER 则将 R_DATE_TESTED, R_RESULT 字段无效。
第二个条件:
如果R_DATE_TESTED < P_DATE_ENCOUNTER 则将最新的R_DATE_TESTED, R_RESULT 字段应用到数据帧,最终结果为:
逻辑结果应该如下:
| P_CLIENT_ID | R_CLIENT_ID | P_DATE_ENCOUNTER | R_DATE_TESTED | R_RESULT |
|---|---|---|---|---|
| 25835 | 25835.0 | 2016-12-21 | NaN | NaN |
| 25835 | 25835.0 | 2017-02-21 | NaN | NaN |
| 25835 | 25835.0 | 2017-04-25 | 2017-03-07 | 20.0 |
| 25835 | 25835.0 | 2017-06-21 | 2017-03-07 | 20.0 |
| 25835 | 25835.0 | 2017-09-04 | 2017-08-03 | 20.0 |
| 25835 | 25835.0 | 2018-01-08 | 2017-08-03 | 20.0 |
| 25835 | 25835.0 | 2018-04-03 | 2018-03-23 | 20.0 |
注意:实际数据集相当大:df1 ~ 700000 行和 df2 ~ 125000 行
代码尝试
import pandas as pd
import numpy as np
df1 = pd.DataFrame({'P_CLIENT_D': ['25835','25835','25835','25835','25835','25835','25835'],
'P_DATE_ENCOUNTER': ['2016-12-21','2017-02-21','2017-04-25','2017-06-21','2017-09-04','2018-01-08','2018-04-03']})
df2 = pd.DataFrame({'R_CLIENT_ID': ['25835','25835','25835','25835','25835','25835','25835'],
'R_DATE_TESTED': ['2017-03-07','2017-08-03','2018-03-23','2019-06-28','2019-08-19','2020-04-20','2021-06-03'],
'R_RESULT':[20,20,20,20,42,40,20]})
df_merged = pd.merge(df1, df2, left_on=['P_CLIENT_D'], right_on = ['R_CLIENT_ID'], how='left')
df_merged = df_merged.drop_duplicates(subset=['P_CLIENT_D', 'P_DATE_ENCOUNTER'], keep='last')
df_merged['FLAG_LAB_AFTER_VISIT'] = 0
df_merged.loc[df_merged.R_DATE_TESTED >= df_merged.P_DATE_ENCOUNTER,'FLAG_LAB_AFTER_VISIT']=1
print(df_merged['FLAG_LAB_AFTER_VISIT'].sum(), 'future labs set to null')
#now the rows with flags - set all lab fields to null
df_merged.loc[df_merged['FLAG_LAB_AFTER_VISIT']==1, df2.columns] = np.nan
【问题讨论】:
-
这不是一项非常艰巨的任务,如果您花时间展示您的尝试,并提供复制这些示例表的代码以便人们可以轻松地获取一些测试数据。
标签: python pandas dataframe merge pandas-groupby