如何在不改变对象内部的对象的情况下合并数组中的多维对象答案

【问题标题】：how to merge multidimensional objects in array without altering the objects inside objects如何在不改变对象内部的对象的情况下合并数组中的多维对象
【发布时间】：2018-03-25 20:44:44
【问题描述】：

您好 :) 我需要以下方面的帮助：

我有这个：

[{"Condenser /Heat Pump":{"2":299,"starttime":"10/05/17","productClass":"Condenser /Heat Pump"}},
{"Condenser /Heat Pump":{"1":2529,"2":2270,"starttime":"10/06/17","productClass":"Condenser /Heat Pump"}},
{"Coorporate Coils":{"2":104,"3":216,"starttime":"10/05/17","productClass":"Coorporate Coils"}},
{"Coorporate Coils":{"1":1107,"2":811,"3":0,"starttime":"10/06/17","productClass":"Coorporate Coils"}}]

我想这样得到它：

[{"Condenser /Heat Pump":{"2":299,"starttime":"10/05/17","productClass":"Condenser /Heat Pump"},{"1":2529,"2":2270,"starttime":"10/06/17","productClass":"Condenser /Heat Pump"}},{"Coorporate Coils":{"2":104,"3":216,"starttime":"10/05/17","productClass":"Coorporate Coils"},{"1":1107,"2":811,"3":0,"starttime":"10/06/17","productClass":"Coorporate Coils"}}]

我一直在尝试找到一种方法来做到这一点，但不幸的是我没能做到。到目前为止，我只能做一些非常不灵活的事情：

var hp=[];
var cc=[];

for(i=0; i<mergedProductClasses.length; i++){
    Object.getOwnPropertyNames(mergedProductClasses[i]).forEach(
       function (val, idx, array) {
         if(val =="Condenser /Heat Pump"){
            hp.push(mergedProductClasses[i]["Condenser /Heat Pump"])
         }else if(val =="Coorporate Coils"){
           cc.push(mergedProductClasses[i]["Coorporate Coils"])
         }
       }
     )
 }

这有点工作......它给了我一些可以使用的东西但是我有多个“vals”所以如果我添加一个新的，我将不得不每次都编辑我的代码来添加那个异常......我想看看是否有一种方法可以更有效地做到这一点......而且我知道我目前的方法并不能完全满足我的需求，但这种格式允许我用数据做我需要的事情。对不起，如果这太基本了 x_x

我试过这个Merge duplicate multidimensional objects in array of objects，但这种方法合并了我所有的对象而不考虑日期，我关心日期。

【问题讨论】：

标签： javascript arrays object merge

【解决方案1】：

不要使用硬编码的键，而是创建一个包含键的数组，并检查该对象是否已存在于该数组中。

这段代码可能不是你要找的，但应该让你明白我在说什么：

var products = [{
    "Condenser /Heat Pump": {
      "2": 299,
      "starttime": "10/05/17",
      "productClass": "Condenser /Heat Pump"
    }
  },
  {
    "Condenser /Heat Pump": {
      "1": 2529,
      "2": 2270,
      "starttime": "10/06/17",
      "productClass": "Condenser /Heat Pump"
    }
  },
  {
    "Coorporate Coils": {
      "2": 104,
      "3": 216,
      "starttime": "10/05/17",
      "productClass": "Coorporate Coils"
    }
  },
  {
    "Coorporate Coils": {
      "1": 1107,
      "2": 811,
      "3": 0,
      "starttime": "10/06/17",
      "productClass": "Coorporate Coils"
    }
  }
]

var merged = {};
var output = document.getElementById("output")

for (var i = 0; i < products.length; i++ ) {
  Object.getOwnPropertyNames(products[i]).forEach(function(val, idx, array) {
    if (typeof(merged[val]) == "undefined") merged[val] = []
    merged[val].push(products[i][val])
  })
}

output.innerText = JSON.stringify(merged, undefined, 2)

<pre id="output">
</pre>

【讨论】：

【解决方案2】：

这花了很长时间。这就是你要找的东西：

const units = [{"Condenser /Heat Pump":{"2":299,"starttime":"10/05/17","productClass":"Condenser /Heat Pump"}},
{"Condenser /Heat Pump":{"1":2529,"2":2270,"starttime":"10/06/17","productClass":"Condenser /Heat Pump"}},
{"Coorporate Coils":{"2":104,"3":216,"starttime":"10/05/17","productClass":"Coorporate Coils"}},
{"Coorporate Coils":{"1":1107,"2":811,"3":0,"starttime":"10/06/17","productClass":"Coorporate Coils"}}]

const objKey = obj => Object.keys(obj)[0]
const objValue = obj => Object.values(obj)[0]
newObj = {}
let unitName
for (let unit of units) {
  unitName = objKey(unit)
  newObj[unitName] = []
}
let unitData
for (let unit of Object.values(units)) {
  unitData = objValue(unit)
  newObj[objKey(unit)].push(unitData)
}
console.log(newObj)

【讨论】：