NSDictionary 中的字典计数答案

【问题标题】：Dictionary count with in NSDictionaryNSDictionary 中的字典计数
【发布时间】：2017-06-09 18:40:08
【问题描述】：

我正在 NSDictionary 下提取一个字典，其中包含子字典。我必须在表格视图中显示所有这些。项目数、字典完全随机......

 {
        Key = Value;
        Key = Value;
        Key = Value;
        “{Dictionary 1}” =     {
            Key = Value;
            Key = Value;
            Key = Value;
        };
        "{Dictionary 2}” =     {
            Key = Value;
            Key = Value;
        };
        Key = Value;
        Key = Value;
        “{Dictionary 3}” =     {
            Key = Value;
            Key = Value;
            Key = Value;
            Key = Value;
        };
        Key = Value;
    }

如何从这个主 NSDictionary 中获取子词典的数量？

【问题讨论】：

stackoverflow.com/help/mcve

标签： ios swift dictionary count nsdictionary

【解决方案1】：

您可以尝试将值转换为字典，如果可行，则为字典的数量增加计数器。

例如：

let upperDict = ["key":1,
                 "key2":2,
                 "key3":3,
                 "dict1": ["key1":"1", "key2":32],
                 "dict2": ["key1" :1]] as NSDictionary

var innnerDictionariesCount = 0

for (key, value) in upperDict {
    if value as? [String:Any] != nil {
        innnerDictionariesCount += 1
    }
}

【讨论】：

【解决方案2】：

如果你想在一个部分中显示所有内容，我认为你需要知道主字典中有多少个值，而不是有多少子字典。

let mainDic: NSDictionary = ["value1": "value1", 
                             "value2": "value2", 
                             "subDic1": ["value1": "value1", "value2": "value2"],
                             "subDic2": ["value1": "value1", "value2": "value2"] 
                            ]

var counter = 0
for (key, value) in mainDic {
    if value is String {
        counter += 1
    } 
    else if value is Dictionary<String, Any> {
        let subDic = value as! Dictionary<String, Any>
        counter += subDic.count
    }
    else if value is Array<Any> {
        let subArray = value as! Array<Any>
        counter += subArray.count
    }
}

print(counter) // output is 6

【讨论】：