在 Swift 中对字典数组进行排序答案

【问题标题】：Sort Array of Dictionarys in Swift在 Swift 中对字典数组进行排序
【发布时间】：2018-07-17 14:23:30
【问题描述】：

大家好，我正在尝试通过在 swift 中使用 sorted by 对字典数组（[["key": Int, "value": Any]] 格式）进行排序，但它无法正常工作。这是我的字典数组，这些字典包含一个字典，我在子字典中有一个唯一标识符，即“id”，我也有唯一键。请指导我。实际上我的数据格式如下。如何使用“id”获取值对其进行排序（[“isMale”：false，“status”：“”，“name”：“John”，“id”：10）]）

var dataArray  = [(key: 10, value: ["isMale": false, "status": "", "name": "John","id": 10)], (key: 2, value: ["isMale": false, "status": "", "name": "John","id": 2]), (key: 3, value: ["isMale": false, "status": "", "name": "John","id": 3]), (key: 7, value:
 ["isMale": false, "status": "", "name": "John","id": 7]), (key: 9, value: ["isMale": false, "status": "", "name": "John","id": 9]), (key: 4, value: ["isMale": false, "status": "", "name": "John","id": 4]), (key: 6, value: ["isMale": false, "status": "", "name": "John","id": 6]), (key: 5, value: ["isMale": false, "status": "", "name": "John","id": 5]), (key: 8, value: ["isMale": false, "status": "", "name": "John","id": 8]), (key: 11, value: ["isMale": false, "status": "", "name": "John","id": 11])];

var data = [Int:Any]() data = dataArray.sorted(by: { $0 < $1 })

【问题讨论】：

排序的逻辑是什么？换句话说：什么定义了一个特定的 dict 在排序之后应该位于另一个 dict 的较低索引处？
let result = dataArray.sorted(by: {($0["key"] as! Int) < ($1["key"] as! Int)})
排序后我想得到所有的值
实际上我的数据格式如下：[("key":"A", "value":["isMale": false, "status": "", "name": "John" ,"id": 10]), ("key":"B", "value":["isMale": false, "status": "", "name": "John","id": 2) , ("key":"C", "value":["isMale": false, "status": "", "name": "John","id": 3])]

标签： ios arrays swift sorting dictionary

【解决方案1】：

您可以像这样按 value["id"] 变量对dataArray 进行排序：

var dataArray  = [
    (key: 10, value: ["isMale": false, "status": "", "name": "John","id": 10]),
    (key: 2, value: ["isMale": false, "status": "", "name": "John","id": 2]),
    (key: 3, value: ["isMale": false, "status": "", "name": "John","id": 3]),
    (key: 7, value: ["isMale": false, "status": "", "name": "John","id": 7]),
    (key: 9, value: ["isMale": false, "status": "", "name": "John","id": 9]),
    (key: 4, value: ["isMale": false, "status": "", "name": "John","id": 4]),
    (key: 6, value: ["isMale": false, "status": "", "name": "John","id": 6]),
    (key: 5, value: ["isMale": false, "status": "", "name": "John","id": 5]),
    (key: 8, value: ["isMale": false, "status": "", "name": "John","id": 8]),
    (key: 11, value: ["isMale": false, "status": "", "name": "John","id": 11])];

let sorted = dataArray.sorted(by: {
    let id0 = $0.value["id"] as! Int
    let id1 = $1.value["id"] as! Int
    return id0 < id1
})

print(sorted.map { $0.key })

【讨论】：