将列表中的每个元素替换为字典列表中的另一个元素

Question

简而言之，我需要为列表中的每个元素从字典列表中获取相应的值并替换它 例如...对于以下输入列表

list1 = ['gui', 'guigui', 'guiguigguuii']
list2 = ['gui', 'gui', 'gui', 'gui', 'gui', 'gui']

我应该在那些字典列表中查找

dictlist1 = [{'gui': 'ya'}, {'guigui': 'lyub'}, {'guiguigguuii': 'htr'}]
dictlist2 = [{'gui': 'asdf'}]

它应该输出

output1 = ['ya', 'lyub', 'htr']
output2 = ['asdf', 'asdf', 'asdf', 'asdf', 'asdf', 'asdf']

我已经写了一个代码...但是它不适用于第二个数据样本

print(' '.join([item for sublist in [[value for key, value in d.items()] for d in lista] for item in sublist]))

Answer 1

在这里，抱歉，如果它有点长，但是，我认为使用这个模板你可以解决一些问题。

list1 = ['gui', 'guigui', 'guiguigguuii']
replace = [{'gui': 'ya'}, {'guigui': 'lyub'}, {'guiguigguuii': 'htr'}]
newList = []
#iterate through list1
for words in list1:
    count = 0
    #iterate through replaces dicts
    for dicts in replace:
        #Check if any word in list1 can be replaced
        if words == list(dicts.keys())[0]:newList.append(dicts[list(dicts.keys())[0]])
        count += 1
print(newList)

输出

['ya', 'lyub', 'htr']