在Python中访问嵌套字典中键的第二个实例

Question

所以我正在使用GMusicAPI 尝试与 Google Play 音乐（我正在使用 MobileClient 视图）进行一些交互。不幸的是，它只在 Python 中，这是一种我以前从未使用过的语言。我正在运行搜索，它将搜索给定的艺术家。我遇到的问题是，有些艺术家，我想要的艺术家不是第一个结果。

我的解决方案是只搜索（此搜索返回字典）前 5-10 名艺术家，然后遍历他们，直到字典键中的名称与搜索查询匹配。

这是我从搜索中返回的字典部分。这就是"artist_hits" 部分。

[{'artist': {'name': 'Tiësto', 'artistArtRef': 'http://lh3.googleusercontent.com/wfrs3FuLMoZ7MMfESLOE7kXw9pR9usqZsR-OCo7GW544aqHfj_WMo_YYeETdAmUGQU9fJW7D', 'artistArtRefs': [{'kind': 'sj#imageRef', 'autogen': False, 'url': 'http://lh3.googleusercontent.com/wfrs3FuLMoZ7MMfESLOE7kXw9pR9usqZsR-OCo7GW544aqHfj_WMo_YYeETdAmUGQU9fJW7D', 'aspectRatio': '2'}], 'kind': 'sj#artist', 'artistId': 'Agzf4r7d54azste62qh6z2q7bcy', 'artist_bio_attribution': {'license_url': 'http://creativecommons.org/licenses/by-sa/4.0/legalcode', 'kind': 'sj#attribution', 'source_title': 'Wikipedia', 'license_title': 'Creative Commons Attribution CC-BY-SA 4.0', 'source_url': 'http://en.wikipedia.org/wiki/Ti%C3%ABsto'}}, 'type': '2'}, 

{'artist': {'name': 'Skrillex', 'artistArtRef': 'http://lh3.googleusercontent.com/wUw1KU9e6VOO7tSNFjKvCljL05Fud1w5mvt8UTbs5G7fBS4sFGphEOIs0EUXBwF9CHuGFEufgQ', 'artistArtRefs': [{'kind': 'sj#imageRef', 'autogen': False, 'url': 'http://lh3.googleusercontent.com/wUw1KU9e6VOO7tSNFjKvCljL05Fud1w5mvt8UTbs5G7fBS4sFGphEOIs0EUXBwF9CHuGFEufgQ', 'aspectRatio': '2'}], 'kind': 'sj#artist', 'artistId': 'Aqy2vtuiohb4rdrakrtbphxbdme', 'artist_bio_attribution': {'kind': 'sj#attribution', 'source_title': 'artist representative'}}, 'type': '2'}, 

{'artist': {'kind': 'sj#artist', 'artistId': 'Achiqpfv5ncaoobeiu6vfmf2jf4', 'name': 'Marshmello', 'artistArtRef': 'http://lh3.googleusercontent.com/KAqga3a8rX1Tam5FSyWGUcT56Zm9uDoyei2vty1Xra8CApKn1vi5Nb9-nNt70U4Q6rtuOA9KXQ', 'artistArtRefs': [{'kind': 'sj#imageRef', 'autogen': True, 'url': 'http://lh3.googleusercontent.com/KAqga3a8rX1Tam5FSyWGUcT56Zm9uDoyei2vty1Xra8CApKn1vi5Nb9-nNt70U4Q6rtuOA9KXQ', 'aspectRatio': '2'}, {'kind': 'sj#imageRef', 'autogen': True, 'url': 'http://lh3.googleusercontent.com/Zp3xcR0sc0LDnFuYy7sY-l8ggvEmPjFK_UruOSaZk25jKIYZKDsZA382WIyXqptClH91oI7QzQ', 'aspectRatio': '1'}]}, 'type': '2'}, 

{'artist': {'name': 'deadmau5', 'artistArtRef': 'http://lh3.googleusercontent.com/rNh6zCCuiJCgEWldulkYIbpfP33W9K0ULAPsWrDThPdz_naqHR_bznxRFgoOwMRr5V0ur-O-', 'artistArtRefs': [{'kind': 'sj#imageRef', 'autogen': False, 'url': 'http://lh3.googleusercontent.com/rNh6zCCuiJCgEWldulkYIbpfP33W9K0ULAPsWrDThPdz_naqHR_bznxRFgoOwMRr5V0ur-O-', 'aspectRatio': '2'}], 'kind': 'sj#artist', 'artistId': 'Atngmlxlixottlthpcypidmxlu4', 'artist_bio_attribution': {'license_url': 'http://creativecommons.org/licenses/by-sa/4.0/legalcode', 'kind': 'sj#attribution', 'source_title': 'Wikipedia', 'license_title': 'Creative Commons Attribution CC-BY-SA 4.0', 'source_url': 'http://en.wikipedia.org/wiki/Deadmau5'}}, 'type': '2'}, 

{'artist': {'kind': 'sj#artist', 'artistId': 'A3akm3hkaas6r4mp3nmhn2d7vom', 'name': 'Marshmello', 'artistArtRef': 'http://lh3.googleusercontent.com/sU63V5nC1xAYuYLfd-WCzmfP5Z1iYslm8xntUe6HPVRmvIEs9QCwaxRgcaQy1Eh8HbSEwEMunQ', 'artistArtRefs': [{'kind': 'sj#imageRef', 'autogen': True, 'url': 'http://lh3.googleusercontent.com/sU63V5nC1xAYuYLfd-WCzmfP5Z1iYslm8xntUe6HPVRmvIEs9QCwaxRgcaQy1Eh8HbSEwEMunQ', 'aspectRatio': '2'}, {'kind': 'sj#imageRef', 'autogen': True, 'url': 'http://lh4.ggpht.com/6cv48SUFmOIXMjXmgs6KCw6NViHEQ2w2YRN2hhQ6HBAcVggh9-L882bYwH5VKZ2YqloodT3rNg', 'aspectRatio': '1'}]}, 'type': '2'}, 

{'artist': {'kind': 'sj#artist', 'artistId': 'Aatki3zj7b6fnemq2qldpjmfg74', 'name': 'Marshmellow Overcoat', 'artistArtRef': 'http://lh3.googleusercontent.com/-0spMaLVdzkwkoLgfNPAAL-KMUX1ulOYEMN7sAs_i2kZtFhq-CmPCKHECF_wRtKeTUnFWKViPg', 'artistArtRefs': [{'kind': 'sj#imageRef', 'autogen': True, 'url': 'http://lh3.googleusercontent.com/-0spMaLVdzkwkoLgfNPAAL-KMUX1ulOYEMN7sAs_i2kZtFhq-CmPCKHECF_wRtKeTUnFWKViPg', 'aspectRatio': '2'}, {'kind': 'sj#imageRef', 'autogen': True, 'url': 'http://lh3.ggpht.com/BfiwEzdKnrAonw4myuyPu6p7GlsAhpd3ZA4E4wQQ-rkygRikCYKRwOWTTM1y3C2oYhPkqXsq0Q', 'aspectRatio': '1'}]}, 'type': '2'}, 

{'artist': {'kind': 'sj#artist', 'artistId': 'Aik7qbnj6ml3i7fpya4rwxjswqq', 'name': 'Marshmellow', 'artistArtRef': 'http://lh3.googleusercontent.com/9UXduVP_4LP702bqvQKU8NKBh9sH_1P9LLYXYQ_IcRcVQUNXqMiSY1dykYdWlGR21NsakeOK', 'artistArtRefs': [{'kind': 'sj#imageRef', 'autogen': True, 'url': 'http://lh3.googleusercontent.com/9UXduVP_4LP702bqvQKU8NKBh9sH_1P9LLYXYQ_IcRcVQUNXqMiSY1dykYdWlGR21NsakeOK', 'aspectRatio': '2'}, {'kind': 'sj#imageRef', 'autogen': True, 'url': 'http://lh3.googleusercontent.com/xmuuJ_XtgD1CBq7ZBKYZdo0gp7s9oiXZeNQ1lEhDfsXIWhAv2JD3w7IyM54y5OFpw8cAOEaV2Q', 'aspectRatio': '1'}]}, 'type': '2'}]

我的问题是如何访问第一个 "artist" 键之后的任何内容？我需要从中获取 "name" 和 "artistId" 值。我这样称呼第一个。

ArtistSearch['artist_hits'][0]['artist']['name']

而且效果很好。但是我尝试像这样访问该键的第二个实例

ArtistSearch['artist_hits'][0]['artist'][1]['name']

而且它不起作用。任何帮助将不胜感激。

Answer 1

我想你想要的是：

ArtistSearch['artist_hits'][1]['artist']['name']
#                        ---^---

因为ArtistSearch['artist_hits'] 是列表，所以您需要第二个字典[1] 和其中的['artist']['name'] 字段