从字符串中删除所有非单词字符（标点符号）

Question

好的，这是我第一次发帖，如有错误请见谅。长话短说，我得到了一个字符串数组，我的目标是计算字符串中唯一单词的数量，并从数组中删除任何标点符号。

public static HashMap<String, Integer> uniqueWords(String[] book) {
    HashMap<String, Integer> hm = new HashMap<>();

    for (int i = 0; i < book.length; i++) {
        if (hm.containsKey(book[i])) {
            hm.put(book[i], hm.get(book[i]) + 1);
        } else {
            book[i] = book[i].replaceAll("[^a-zA-Z]","").replaceAll("\\p{Punct}","").replaceAll("\\W+","").replaceAll("\\n","").toLowerCase();
            hm.put(book[i], 1);
        }
    }
    return hm;
}

输入：{“Redfish”、“redfish”、“redfish”、“Bluefish”、“bluefish”、“bluefish”、“*”、“%”、“”}；

输出：{=2, bluefish=3, redfish=3}

所以我已经成功地删除了所有空白，但我仍然有星号和百分位数正在计算中。

感谢您的帮助，谢谢。

Answer 1

试试这样的——

    public static HashMap<String, Integer> uniqueWords(String[] book) {
    HashMap<String, Integer> hm = new HashMap<>();
string strBook = "";
int key = 1;
    for (int i = 0; i < book.length; i++) {
    strBook= book[i].replaceAll("[^a-zA-Z]","").replaceAll("\\p{Punct}","").replaceAll("\\W+","").replaceAll("\\n","").toLowerCase();
        if (!hm.containsKey(strBook)) {
            hm.put(key, strBook);
            key++;
        }
    }
    return hm;
}