将 python dict 或 csv 文件转换为数据框

Question

我有一个字典转储为 csv，如下所示。我如何将其转换为数据框 X,Y,SN 作为标题？我正在考虑编写一个 for 循环并使用 split 但它似乎不是很优雅也没有效率......

"49,42",001C0BA79A44
"49,43",001C0BA79A46
"49,40",001C0BA79A40
"49,41",001C0BA79A42
"67,22",001C0BA791E8
"65,31",001C0BA7991E
"67,23",001C0BA793BA
"64,25",001C0BA79416
"74,29",001C0BA79354
"65,33",001C0BA79922
"58,12",001C0BA78B2D
"65,32",001C0BA79920
"72,36",001C0BA79E08
"49,31",001C0BA79525
"65,51",001C0BA7A834
"62,46",001C0BA7A729
"49,30",001C0BA79523
"66,40",001C0BA79F45
"52,42",001C0BA7A07E
"58,17",001C0BA78F49
"52,40",001C0BA79A5E
"52,41",001C0BA79A60
"52,46",001C0BA7A0B8
"52,44",001C0BA7A082
"64,20",001C0BA791AD
"55,29",001C0BA7963E
"55,28",001C0BA7963C
"69,48",001C0BA7A689
"58,15",001C0BA78F45
"55,21",001C0BA79136
"55,20",001C0BA79134
"55,23",001C0BA7913A
"55,22",001C0BA79138
"55,25",001C0BA794A1
"55,24",001C0BA7949F

Answer 1

不要使用for 循环，向现有数据帧添加行效率不高。

def split(string):
     return string.split(',', 1)

df = pd.read_csv(file_path, header=None, names=['Cord', 'SN'])
df['X'], df['Y'] = zip(*df.Cord.map(split))
df = df[['X', 'Y', 'SN']]

请参阅文档here。