跟踪未定义的变量

Question

我正在基于名为 War 的游戏构建一个简单的纸牌游戏。它适用于两个玩家，但我需要对其进行修改以适用于用户一开始输入的任意数量的玩家。我无法弄清楚如何跟踪球员和得分，因为我不再有具体的变量可以使用（无法为每个可能的球员创建一个变量，所以球员是动态添加的）。我碰壁了，不知道从这里去哪里。

这是我的主要方法：

System.out.println("Welcome to War! How many players are playing?"); //User prompt
    Scanner scanner = new Scanner(System.in); //Scanner init
    int numberOfPlayers = scanner.nextInt();//set number of players to next integer entered

    ArrayList<String> deck = createDeck(numberOfPlayers);

    ArrayList<String> playerNames = new ArrayList<String>();
    Map<String, Integer> players = new HashMap<String, Integer>();

    System.out.println("Enter player name");

    for (int p = 0; p <= numberOfPlayers; p++) {
        String playerID = scanner.next();
        addPlayer(playerID);
        players.put(playerID, 100);
        playerNames.add(playerID);
    }

        for (int j = createDeck(numberOfPlayers).size(); j > 0; j = j - numberOfPlayers) {  //j is set to deck length. Increment down two number each loop. 

            String readString = scanner.nextLine(); //Set variable "readString" to user input
            int score = 0;

            if (readString.equals("")) {    //If user input equals "enter"...

                ArrayList<Integer> currentScore = new ArrayList<Integer>();

                for (int q = 0; q <= numberOfPlayers; q++){

                    score = checkValue(deck);
                    String name = playerNames.get(q);
                    currentScore.add(score);
                    System.out.println(name +" drew a "+ deck.get(0) + " worth " + score + " points!"); //Print player 1's card


                    deck.remove(0); //Remove card
                    players.put(name, players.get(name).intValue() - score);
                }System.out.println(players.values());

            }
        }

此方法检查抽出的牌的值并分配一个点值。

int currentScore = 0;

    boolean checkAce = deck.get(0).startsWith("Ace");
    boolean checkTwo = deck.get(0).startsWith("Two");
    boolean checkThree = deck.get(0).startsWith("Three");
    boolean checkFour = deck.get(0).startsWith("Four");
    boolean checkFive = deck.get(0).startsWith("Five");
    boolean checkSix = deck.get(0).startsWith("Six");
    boolean checkSeven = deck.get(0).startsWith("Seven");
    boolean checkEight = deck.get(0).startsWith("Eight");
    boolean checkNine = deck.get(0).startsWith("Nine");
    boolean checkTen = deck.get(0).startsWith("Ten");
    boolean checkJack = deck.get(0).startsWith("Jack");
    boolean checkQueen = deck.get(0).startsWith("Queen");
    boolean checkKing = deck.get(0).startsWith("King");


    if (checkAce) {
        currentScore = 14;
    }else if (checkTwo) {
        currentScore = 2;
    }else if (checkThree) {
        currentScore = 3;
    }else if (checkFour) {
        currentScore = 4;
    }else if (checkFive) {
        currentScore = 5;
    }else if (checkSix) {
        currentScore = 6;
    }else if (checkSeven) {
        currentScore = 7;
    }else if (checkEight) {
        currentScore = 8;
    }else if (checkNine) {
        currentScore = 9;
    }else if (checkTen) {
        currentScore = 10;
    }else if (checkJack) {
        currentScore = 11;
    }else if (checkQueen) {
        currentScore = 12;
    }else if (checkKing) {
        currentScore = 13;
    }


    return currentScore;

}

我的主要问题是什么是处理未知数量的多个玩家的最佳方式，以使我能够跟踪分数并宣布获胜者。到目前为止，我所拥有的内容会打印出我的名字以及他们每轮获得多少分，但我没有办法操纵或相互比较这些值。

我使用dictionary 让玩家key 与分数value 相关联。

编辑：任何不包含多个类的解决方案都是首选。

Answer 1

您可以在每一轮结束时对您的Hashmap 进行排序。然后您将打印出第一个元素作为值。这是赢得胜利的最简单方法。

例如，您可以使用以下方法进行排序：

public static <K,V extends Comparable<? super V>> 
            List<Entry<K, V>> entriesSortedByValues(Map<K,V> map) {

    List<Entry<K,V>> sortedEntries = new ArrayList<Entry<K,V>>(map.entrySet());

    Collections.sort(sortedEntries, 
            new Comparator<Entry<K,V>>() {
                @Override
                public int compare(Entry<K,V> e1, Entry<K,V> e2) {
                    return e2.getValue().compareTo(e1.getValue());
                }
            }
    );

    return sortedEntries;
}

那么您只需拨打：entriesSortedByValues(players);

示例来自这里： Sorting the Map<Key,Value> in descending order based on the value

更新： 您可以通过将score 与best 的值进行比较，为每一轮中的最佳玩家存储index，例如：

int best = 0, index = 0;
for (int q = 0; q <= numberOfPlayers; q++){
   score = checkValue(deck);
   if (best < score){
      index = q;
      best = score;
   }
   String name = playerNames.get(q);
   currentScore.add(score);
   System.out.println(name +" drew a "+ deck.get(0) + " worth " + score + " points!"); //Print player 1's card
   deck.remove(0); //Remove card
   players.put(name, players.get(name).intValue() - score);
   }
System.out.println("Best player in this round: " + playerNames.get(index);