【问题标题】:Java Servlet - cannot find symbol - Objects in the same folderJava Servlet - 找不到符号 - 同一文件夹中的对象
【发布时间】:2019-02-01 13:58:56
【问题描述】:

我写了以下两个类:

设备.java

class Equipment{

  private int id;
    private String name;
    private String local;

  public void setId(int id){
    this.id = id;
  }

  public void setName(String n){
    this.name = n;
  }
  public void setLocal(String l){
    this.local = l;
  }

  public int getId(){
    return this.id;
  }

  public String getName(){
    return this.name;
  }
  public String getLocal(){
    return this.local;
  }

}

JDBCCommands.java

import java.util.*;
import java.sql.*;

class JDBCCommands{
  private static Connection con = new ConnectionFactory().getConnection();

  public static void Create(String name, String local){
    String sql = "insert into equipment (name,local) values (?,?)";
    try{
      PreparedStatement ps = con.prepareStatement(sql);
      ps.setString(1, name);
      ps.setString(2, local);
      ps.execute();
      ps.close();
    }catch(SQLException erro_sql){
      throw new RuntimeException(erro_sql);
    }
  }

  public static List<Equipment> Show(){
    List <Equipment> Components = new ArrayList <Equipment> ();
    String sql = "select * from equipment";
    try{
      PreparedStatement ps = con.prepareStatement(sql);
      ResultSet rs = ps.executeQuery();
      while(rs.next()) {
        Equipment e = new Equipment();
        e.setId(Integer.parseInt(rs.getString("equip_id"))  );
        e.setName(rs.getString("nome"));
        e.setLocal(rs.getString("local"));
        Components.add(e);
      }
      rs.close();
      ps.close();
      return Components;
    }catch(SQLException erro_sql){
      throw new RuntimeException(erro_sql);
    }
  }

  public static void Update(int id, String name, String local){
    String sql = "update equipment set name = ?, local = ? where equip_id = ?";
    try{
      PreparedStatement ps = con.prepareStatement(sql);
      ps.setString(1, name);
      ps.setString(2, local);
      ps.setInt(3, id);
      ps.execute();
      ps.close();
    }catch(SQLException erro_sql){
      throw new RuntimeException(erro_sql);
    }
  }

  public static void Delete(int id){
    String sql = "delete from equipment where equip_id = ?";
    try{
      PreparedStatement ps = con.prepareStatement(sql);
      ps.setInt(1, id);
      ps.execute();
      ps.close();
    }catch(SQLException erro_sql){
      throw new RuntimeException(erro_sql);
    }
  }

  public static List<Equipment> Search(String name, String local){
    List <Equipment> Components = new ArrayList <Equipment> ();
    String sql = "select * from equipment where name like ? and local like ?";
    try{
      PreparedStatement ps = con.prepareStatement(sql);
      ps.setString(1, "%" + name + "%");
      ps.setString(2, "%" + local + "%");
      ResultSet rs = ps.executeQuery();
      while(rs.next()) {
        Equipment e = new Equipment();
        e.setId(Integer.parseInt(rs.getString("equip_id"))  );
        e.setName(rs.getString("nome"));
        e.setLocal(rs.getString("local"));
        Components.add(e);
      }
      rs.close();
      ps.close();
      return Components;
    }catch(SQLException erro_sql){
      throw new RuntimeException(erro_sql);
    }
  }
}

我用这个类进行了测试,效果很好

import java.util.*;
import java.sql.*;

class MainTest{
  public static void main(String[] args) throws SQLException {
    JDBCCommands jdbc = new JDBCCommands();
    //jdbc.Create("Teste novo", "Novo Teste");
    for(Equipment c : jdbc.Show()){
      System.out.print(c.getId() + " ");
      System.out.print(c.getName() + " ");
      System.out.print(c.getLocal() + "\n");

    }
    System.out.println("-------------------------------------");
    for(Equipment c : jdbc.Search("est n" , "est")){
      System.out.print(c.getId() + " ");
      System.out.print(c.getName() + " ");
      System.out.print(c.getLocal() + "\n");

    }
  }
}

问题是当我尝试这个类时:

import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;

import java.sql.*;

class ListEquipment extends HttpServlet {
  protected void service(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException {

        PrintWriter out = response.getWriter();
        JDBCCommands jdbc = new JDBCCommands();

        System.out.println("<table style=\"width:100%\">");
        for(Equipamento c : jdbc.Show()){
          System.out.println("<tr>");
          System.out.print("<th>" + c.getId() + "</th>");
          System.out.print("<th>" + c.getName() + "</th>");
          System.out.print("<th>" + c.getLocal() + "</th>");
          System.out.println("</tr>");
        }
        System.out.println("</table>");
    }
}

它显示了这个错误:

ListEquipment.java:13:错误:找不到符号

    JDBCCommands jdbc = new JDBCCommands();
    ^

符号:类 JDBCCommands

位置:ListEquipment 类

ListEquipment.java:13:错误:找不到符号

    JDBCCommands jdbc = new JDBCCommands();
                            ^

符号:类 JDBCCommands

位置:ListEquipment 类

ListEquipment.java:16:错误:找不到符号

    for(Equipment c : jdbc.Show()){
        ^

符号:设备类

位置:ListEquipment 类

3 个错误

所有文件都在同一个文件夹中,并且名称正确。我该如何解决这个问题?

【问题讨论】:

  • 也许让你的课程公开。
  • 检查servlet和JDBCCommand类是否在同一个包中
  • 清理你的项目。在 Eclipse 中转到项目-> 清洁。在 intelij 中转到 File -> Invalidate caches。然后编译你的项目。希望对你有帮助
  • @DevilsHnd 我公开了这些课程,但没有用。
  • @Prabath JDBCCommand 与 servlet 位于完全相同的文件夹中。

标签: java mysql apache oop servlets


【解决方案1】:

我只需要将.jar文件,用于与MariaDB的连接,放在lib文件夹中,现在一切正常。

【讨论】:

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