Javascript从带有参数的构造函数调用原型方法[重复]

Question

我试图从教授构造函数内部调用 Person.showInfo()，并将其名称和年龄作为参数。可能吗？。请看下面的评论谢谢。

var Person = function(_name, _age) {
    this.name = _name;
    this.age = _age;
}

Person.prototype.showInfo = function() {
    console.log(this.name, this.age);
};

var Professor = function(_name, _age, _course) {
    Person.call(this, _name, _age);
    this.course = _course;
};

Professor.prototype = Object.create(Person.prototype);
Professor.prototype.constructor = Professor;

Professor.prototype.showInfo = function() {
    // How to call Person.showInfo() here ???
    // Person.prototype.showInfo() ...showing the Professor's name and age
    console.log(this.course);
};

Answer 1

Person.prototype.showInfo.call(this);

只需按原样调用函数，但更改上下文。