Python将表单数据从CSV文件输入到本地HTML文件答案

【问题标题】：Python to input form data from CSV file to local HTML filePython将表单数据从CSV文件输入到本地HTML文件
【发布时间】：2018-11-03 17:08:43
【问题描述】：

我目前正在尝试编写一个 python 脚本来从本地保存的 csv 文件中提取特定数据，然后将该数据输入到网站并单击提交。我已成功提取数据，但无法使用 mechanize 模块打开文件。

如果有另一种方法我只是认为 python 将是完成这项任务的最简单方法，我愿意使用不同的语言。任何反馈将不胜感激。 `

import datetime
import webbrowser
import csv
import mechanize


now = datetime.datetime.now()
mont = now.month
mon = mont + 2
with open(r'\\MyDataNEE\user$\bat0km4\Desktop\automation.csv') as f:
    mycsv = csv.reader(f)
    mycsv = list(mycsv)
    osha = mycsv[mon][2]
    occasional = mycsv[mon][3]
    fleet = mycsv[mon][4]
print(osha)
print(occasional)
print(fleet)

url = r"\\mydatanee\user$\bat0km4\Documents\test.html"

br = mechanize.Browser()
br.set_handle_robots( False )
br.open(url)



br.form['osh'] = osha
br.form['occasion'] = occasional
br.form['flee'] = fleet

br.submit()

` 更新：这是我的 html 代码，以防可能出现问题

<!DOCTYPE html>
<html>
<head></head>

<body>
    <script type="text/javascript">
            function show_confirm()
            {
                var r = confirm("Please Confirm that all values are correct. \nPress ok to submit");
                if (r == true)
                {
                    alert(document.getElementById('osh').value + " " + document.getElementById('occasion').value + " " + document.getElementById('flee').value);
                    return true;
                }
                else
                {
                    return false;
                }
            }

    </script>
    <h1 align="center" style="color: black; font-size: 30pt; font-weight: bolder;">
            Safety Indicator 
    </h1>

    <form name="input" onsubmit="show_confirm();" method = "get">
            <table align="center" border="0" cellspacing="4" cellpadding="0">
                <tbody>
                    <tr>
                        <td>
                            OSHA Injuries
                        </td>
                        <td> 
                            <input id = "osh" name="osha" type="text">
                        </td>
                    </tr>
                    <tr>
                        <td>
                            Occasional Use Incidents
                        </td>
                        <td> 
                            <input id = "occasion" name="occasional" type="text"> 
                        </td>
                    </tr>
                    <tr>
                        <td>
                            Fleet Incidents
                        </td>
                        <td> 
                            <input id = "flee" name="fleet" type="text">
                        </td>
                    </tr>
                </tbody>
            </table>
            <div align="center">
                <input type="submit" value="Submit">
            </div>
        </form>

</body>
</html>

UPDATE ：我使用了通过将 file:// 放在前面建议的文件类型，现在我收到了这个错误。我应该在我的 html 文件中放置一些东西以允许 mechanize 执行此操作吗？ 谁能确认 mechanize 实际上具有与本地 html 文件交互的能力？我很难找到以这种方式使用机械化的人

    C:\Python27>python pyth.py
0
1
2
Traceback (most recent call last):
  File "pyth.py", line 24, in <module>
    br.open(url)
  File "C:\Python27\lib\site-packages\mechanize\_mechanize.py", line 254, in open
    return self._mech_open(url_or_request, data, timeout=timeout)
  File "C:\Python27\lib\site-packages\mechanize\_mechanize.py", line 284, in _mech_open
    response = UserAgentBase.open(self, request, data)
  File "C:\Python27\lib\site-packages\mechanize\_opener.py", line 195, in open
    response = urlopen(self, req, data)
  File "C:\Python27\lib\site-packages\mechanize\_urllib2_fork.py", line 352, in _open
    '_open', req)
  File "C:\Python27\lib\site-packages\mechanize\_urllib2_fork.py", line 340, in _call_chain
    result = func(*args)
  File "C:\Python27\lib\site-packages\mechanize\_urllib2_fork.py", line 1324, in file_open
    return self.parent.open(req)
  File "C:\Python27\lib\site-packages\mechanize\_mechanize.py", line 254, in open
    return self._mech_open(url_or_request, data, timeout=timeout)
  File "C:\Python27\lib\site-packages\mechanize\_mechanize.py", line 284, in _mech_open
    response = UserAgentBase.open(self, request, data)
  File "C:\Python27\lib\site-packages\mechanize\_opener.py", line 195, in open
    response = urlopen(self, req, data)
  File "C:\Python27\lib\site-packages\mechanize\_urllib2_fork.py", line 352, in _open
    '_open', req)
  File "C:\Python27\lib\site-packages\mechanize\_urllib2_fork.py", line 340, in _call_chain
    result = func(*args)
  File "C:\Python27\lib\site-packages\mechanize\_urllib2_fork.py", line 1384, in ftp_open
    raise URLError('ftp error: no host given')

【问题讨论】：

请将错误粘贴为代码 sn-ps 而不是图像
添加您遇到的错误
路径为本地UNC网络路径。将file:// 添加到url（不是http）。您可以将所有斜杠交换为/。例如。 file://///mydatanee/user$/bat0km4/Documents/test.html

标签： python html forms input mechanize

【解决方案1】：

回答我最终下载了 Xampp，我可以使用 apache 在本地托管我的 html 文件，这解决了我的问题。我仍然想知道 mechanize 是否能够自行访问本地 html 文件。

【讨论】：