【发布时间】:2020-10-04 11:00:21
【问题描述】:
class (BASE, db.Model):
__tablename__ = ''
id = db.Column(db.Integer, primary_key=True)
advertiser_id = db.Column(db.Integer)
name = db.Column(db.String(255))
class (BASE, db.Model):
__tablename__ = ''
id = db.Column(db.Integer, primary_key=True)
advertiser_id = db.Column(db.Integer)
name = db.Column(db.String(255))
两个表结构相同,如何用pageIndex和pageSize查询和分页?
**one table**
.query.filter_by(advertiser_id=123).order_by(.id.desc()).paginate(pageIndex, pageSize, False).items
【问题讨论】:
标签: python mysql flask sqlalchemy flask-sqlalchemy