在不重复的情况下获取div内的节点答案

【问题标题】：Get node inside div without duplicating在不重复的情况下获取div内的节点
【发布时间】：2019-10-24 04:32:46
【问题描述】：

我有下面的html代码

<div class = "matches">
<div class = "conf">
Brazil vs. Colombia
</ div>
<div class = "targetHour"> 08:00 pm </ div>
</ div>
</ div>
<div class = "matches">
<div class = "conf">
Chilex Argentina
</ div>
<div class = "targetHour"> 08:00 pm </ div>
</ div>
</ div>

我需要获取父div的值和子div的值，不重复结果。将每场比赛的时间表与各自的家长联系起来。

这是我的python代码

for nc in soup.find_all('div', attrs={'class': 'league-data'}):
    campeonato = nc.text
    for hr in soup.find('div', attrs={'class': 'match row cf'}).findAll("div",recursive=False):
        print(campeonato + "|" + hr.text)

【问题讨论】：

为什么不列出已经收集的项目并从中过滤？

标签： python python-3.x beautifulsoup selenium-chromedriver

【解决方案1】：

您可以使用zip() 函数将比赛与相应的时间表联系起来：

from bs4 import BeautifulSoup

data = '''<div class = "conf">
Brazil vs. Colombia
</div>
<div class = "targetHour"> 08:00 pm </div>
</div>
</div>
<div class = "matches">
<div class = "conf">
Chilex Argentina
</div>
<div class = "targetHour"> 08:00 pm </div>
</div>
</div>'''

soup = BeautifulSoup(data, 'lxml')

for match, hour in zip( soup.select('div.conf'), soup.select('div.targetHour') ):
    print(match.text.strip(), hour.text.strip())

打印：

Brazil vs. Colombia 08:00 pm
Chilex Argentina 08:00 pm

【讨论】：

【解决方案2】：

另一种选择（假设列表长度为偶数）

from bs4 import BeautifulSoup

data = '''<div class = "conf">
Brazil vs. Colombia
</div>
<div class = "targetHour"> 08:00 pm </div>
</div>
</div>
<div class = "matches">
<div class = "conf">
Chilex Argentina
</div>
<div class = "targetHour"> 08:00 pm </div>
</div>
</div>'''

soup = BeautifulSoup(data, 'lxml')
items = [item.text.strip() for item in soup.select('.conf, .targetHour')]
for i in range(0, len(items), 2):
       print(items[i],items[i+1])

【讨论】：