【问题标题】:Django get display name choicesDjango 获取显示名称选项
【发布时间】:2013-04-05 17:37:51
【问题描述】:

我正在努力寻找解决问题的方法。

models.py

class Article(models.Model):
    title = models.CharField(max_length=100)
    slug = models.SlugField()
    description = models.TextField()

def archive_quality(self):
    return self.archive_set.order_by('-quality').distinct().values_list('quality', flat=True)


class Archive(models.Model):
    CHOICES_QUALITY = (
        ('1', 'HD YB'),
        ('2', 'HD BJ'),
        ('3', 'HD POQD'),
        ('4', 'HD ANBC'),
    )
    article = models.ForeignKey(Article)
    quality = models.CharField(max_length=100, choices=CHOICES_QUALITY)

arhives.html

{% for article in articles %}
    {{ article }}
    {% for quality in article.archive_quality %}
        {{ quality.get_quality_display }}#This is not working
    {% endfor %}
{% endfor %}

更新 函数archive_quality 很重要,因为它可以防止模板对象重复出现。

Example:
article:
   My article one
Archive:
       quality: 1111222333 >> without the function
       quality: 123 >> with function

【问题讨论】:

  • 你能完成你的models.py吗?您的 forloop 错过了模型中的变量
  • @catherine 当然,只需添加完整模型。
  • 所有的选择真的都是'1'吗?
  • @Koterpillar 抱歉,现在修复。

标签: python django templates


【解决方案1】:

选项#1:

models.py

CHOICES_QUALITY = (
    ('1', 'HD YB'),
    ('2', 'HD BJ'),
    ('3', 'HD POQD'),
    ('4', 'HD ANBC'),
)

class Article(models.Model):
    title = models.CharField(max_length=100)
    slug = models.SlugField()
    description = models.TextField()

    def archive_quality(self):
        quality = self.archive_set.order_by('-quality').distinct().values_list(
            'quality', flat=True)
        lists = []
        for q in quality:
            for choice in CHOICES_QUALITY:
                if choice[0] == q:
                    lists.append({'quality': choice[1]})
        return lists

class Archive(models.Model):
    article = models.ForeignKey(Article)
    quality = models.CharField(max_length=100, choices=CHOICES_QUALITY)

模板

{% for article in articles %}
    {% for item in article.archive_quality %}
        {{ item.quality }},
    {% endfor %}
{% endfor %}

选项 #2:

archive_tag.py

from django import template
from app_name.models import CHOICES_QUALITY

register = template.Library()

@register.filter
def quality(q):
    for choice in CHOICES_QUALITY:
        if choice[0] == q:
            return choice[1]
    return ''

模板

{% load archive_tag %}

{% for article in articles %}
    {% for item in article.archive_quality %}
        {{ item|quality }},
    {% endfor %}
{% endfor %}

【讨论】:

  • 哇,感谢所有工作发现。您可以使用 forloop.last 查看是否有第二个对象。感谢您的帮助。
  • return dict(CHOICES_QUALITY).get(q) 更短
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