【发布时间】：2015-06-23 18:58:10
【问题描述】：
我正在尝试从 Google Places 的 API 获取 Android 应用程序的信息。为此，我首先在我的 Google 帐户中启用了此 API。
其次，我为浏览器创建了一个 API KEY。由于另一个 API，我已经有一个 API KEY Server。
所以，在我的代码中，我已经使用这两个键进行了测试，而且我总是得到相同的结果！！！
{
"error_message" : "此服务需要 API 密钥。",
“html_attributions”：[]，
“结果”：[]，
“状态”：“REQUEST_DENIED”
}
我用来拨打电话的代码是...
@Override
protected String doInBackground(LocationService... ls) {
JSONObject result = new JSONObject();
URL url;
HttpsURLConnection urlConnection;
// Making HTTP request
try {
//Define connection
url = new URL("https://maps.googleapis.com/maps/api/place/nearbysearch/json");
urlConnection = (HttpsURLConnection)url.openConnection();
urlConnection.setRequestMethod("POST");
urlConnection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
urlConnection.setRequestProperty("charset", "utf-8");
urlConnection.setRequestProperty("Accept", "application/json");
urlConnection.setDoOutput(true);
urlConnection.setDoInput(true);
urlConnection.setUseCaches(false);
//Send data
String parameters = "?location=" + String.valueOf(ls[0].getLocation().getLatitude()) + "," + String.valueOf(ls[0].getLocation().getLongitude());
parameters+="&radius=5000";
parameters+="&types=restaurant|health|city_hall|gas_station|shopping_mall|grocery_or_supermarket";
parameters+="&sensor=false";
parameters+="&key=" + Constants.API_KEY_BROWSER_APPLICATIONS;
byte[] postData = parameters.getBytes(Charset.forName("UTF-8"));
int postDataLength = postData.length;
urlConnection.setRequestProperty("Content-Length", Integer.toString(postDataLength));
DataOutputStream data = new DataOutputStream(urlConnection.getOutputStream());
data.write(postData);
data.flush();
data.close();
Log.d(TAG, "Datos enviados");
Log.d(TAG, "ResponseCode: " + String.valueOf(urlConnection.getResponseCode()));
//Display what returns POST request
StringBuilder sb = new StringBuilder();
int HttpResult = urlConnection.getResponseCode();
if(HttpResult == HttpURLConnection.HTTP_OK){
String json;
BufferedReader br = new BufferedReader(new InputStreamReader(urlConnection.getInputStream(),"utf-8"));
String line;
while ((line = br.readLine()) != null) {
sb.append(line + "\n");
}
br.close();
//System.out.println(""+sb.toString());
Log.d(TAG, "json: " + sb.toString());
FileService file = new FileService();
file.writeLog(POIActivity.TAG, getClass().getName(), POIActivity.urlConnection + parameters);
file.writeLog(POIActivity.TAG, "doInBackground", sb.toString());
// Parse the String to a JSON Object
result = new JSONObject(sb.toString());
}else{
//System.out.println(urlConnection.getResponseMessage());
Log.d(TAG, "urlConnection.getResponseMessage(): " + urlConnection.getResponseMessage());
result = null;
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
Log.d(TAG, "UnsuppoertedEncodingException: " + e.toString());
} catch (JSONException e) {
e.printStackTrace();
Log.d(TAG, "Error JSONException: " + e.toString());
} catch (IOException e) {
e.printStackTrace();
Log.d(TAG, "IOException: " + e.toString());
}
// Return JSON Object
return result.toString();
}
当我调用 API 时，我得到了类似 ResponseCode = 200 并且我构建的调用最终是这样的......
https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=38.26790166666667,-0.7052183333333333&radius=5000&types=restaurant|health|city_hall|gas_station|shopping_mall|grocery_or_supermarket&sensor=false&key=API_KEY
请记住，像 API_KEY 我都使用过，用于服务器应用程序的 Api Key 和用于浏览器应用程序的 Api Key，我得到了相同的结果。
真诚地，我对这个问题感到绝望，因为我不知道自己做错了什么！！！
【问题讨论】：
标签： java android google-places-api