创建用户 Swift 时的 Firebase 错误处理答案

【问题标题】：Firebase error handling while creating user Swift创建用户 Swift 时的 Firebase 错误处理
【发布时间】：2017-03-21 22:45:47
【问题描述】：

我目前正在开发一个 iOS 应用程序，我想实现 Firebase 数据库。

我在用户创建过程中处理错误时遇到了问题。我总是从开关中得到默认错误，这是我的代码：

FIRAuth.auth()?.createUser(withEmail: emailField.text!, password: passwordField.text!, completion: { (user, error) in
        if (error != nil) {

            if let errCode = FIRAuthErrorCode(rawValue: error!._code) {

                var alertController = UIAlertController(title: "", message: "", preferredStyle: UIAlertControllerStyle.alert)
                let okButton = UIAlertAction(title: "OK", style: UIAlertActionStyle.default) {
                    (result: UIAlertAction) -> Void in
                    print("Error transmitted")
                }

                switch errCode {
                case .errorCodeInvalidEmail:
                    print("Invalid email")
                    alertController = UIAlertController(title: "Error", message: "Email syntax is not correct", preferredStyle: UIAlertControllerStyle.alert)
                    alertController.addAction(okButton)
                    self.present(alertController, animated: true, completion: nil)
                case .errorCodeEmailAlreadyInUse:
                    print("Email already in use")
                    alertController = UIAlertController(title: "Error", message: "This email is already in use", preferredStyle: UIAlertControllerStyle.alert)
                    alertController.addAction(okButton)
                    self.present(alertController, animated: true, completion: nil)
                case .errorCodeWeakPassword:
                    print("Password weak")
                    alertController = UIAlertController(title: "Error", message: "Password is too weak. Please choose a password which contains at least 6 characters.", preferredStyle: UIAlertControllerStyle.alert)
                    alertController.addAction(okButton)
                    self.present(alertController, animated: true, completion: nil)
                default:
                    // ALWAYS GET HERE.
                    print(error)
                    alertController = UIAlertController(title: "Error", message: "An unknown error occured.", preferredStyle: UIAlertControllerStyle.alert)
                    alertController.addAction(okButton)
                    self.present(alertController, animated: true, completion: nil)
                }

            }

        } else {
            print("User created")
            let newUser = ["email": self.emailField.text!]
            let firebaseNewUser = self.ref.childByAutoId()
            firebaseNewUser.setValue(newUser)
        }

此外，打印（错误）显示：

Optional(Error Domain=FIRAuthErrorDomain Code=17999 "An internal error has occurred, 
    print and inspect the error details for more information." 
    UserInfo={NSUnderlyingError=0x170257be0 {
        Error Domain=FIRAuthInternalErrorDomain Code=3 "(null)" 
        UserInfo={FIRAuthErrorUserInfoDeserializedResponseKey={
    code = 400;
    errors =     (
            {
        domain = usageLimits;
        message = "Bad Request";
        reason = keyExpired;
    }
    );
    message = "Bad Request";
}}}, 
error_name=ERROR_INTERNAL_ERROR, 
NSLocalizedDescription=An internal error has occurred, print and inspect the 
    error details for more information.})

有人可以帮帮我吗？

【问题讨论】：

标签： swift firebase error-handling firebase-authentication

【解决方案1】：

尝试在 google 控制台中启用身份工具包 API。

【讨论】：

【解决方案2】：

实际上，（作为对上一条消息的回答），身份工具包 API 已经激活。

问题出在 API 密钥已生成但受限于网站请求这一事实。

解决方案：所以我只是生成了另一个API密钥，将其限制在iOS应用程序中，再次下载.plist，将其放入项目并在其中添加API_KEY（API_KEY作为信息属性和value作为新生成的api键值）

【讨论】：

【解决方案3】：

对于创建的新用户请按照这个简单的代码。请将这段代码放在 Create Button @IBAction 函数中。

FIRAuth.auth()?.createUserWithEmail(Username.text!, password: Password.text!
            , completion: {

                user , error in

                if error != nil {
                 print("Something Went to Wrong :(")
                }

                else {

                    print("Account Created Sucessfully ")
                }


        })

【讨论】：