【发布时间】:2016-07-09 13:44:46
【问题描述】:
这是我保存为 'phpsqlajax.php' 的 xml 代码
<?php
require("db_connect1.php");
function parseToXML($htmlStr)
{
$xmlStr=str_replace('<','<',$htmlStr);
$xmlStr=str_replace('>','>',$xmlStr);
$xmlStr=str_replace('"','"',$xmlStr);
$xmlStr=str_replace("'",''',$xmlStr);
$xmlStr=str_replace("&",'&',$xmlStr);
return $xmlStr;
}
// Opens a connection to a mySQL server
$connection=mysqli_connect ($db_hostname, $db_username, $db_password);
if (!$connection) {
die('Not connected : ' . mysqli_error($connection));
}
// Set the active mySQL database
$db_selected=mysqli_select_db($connection, $db_database);
if (!$db_selected) {
die ('Can\'t use db : ' . mysqli_error($connection));
}
// Select all the rows in the markers table
$query = "SELECT * FROM markers WHERE 1=1";
$result = mysqli_query($connection, $query);
if (!$result) {
die('Invalid query: ' . mysqli_error($connection));
}
header("Content-type: text/xml");
// Start XML file, echo parent node
echo '<markers>';
// Iterate through the rows, printing XML nodes for each
while ($row = @mysqli_fetch_assoc($result)){
// ADD TO XML DOCUMENT NODE
echo '<marker ';
echo 'name="' . parseToXML('&','&', $row['name']) . '" ';
echo 'lat="' . $row['lat'] . '" ';
echo 'lng="' . $row['lng'] . '" ';
echo 'type="' . $row['type'] . '" ';
echo '/>';
}
// End XML file
echo '</markers>';
?>
我正在尝试下载它并将其实现到我的地图上,该地图保存为“mapxml.html”,但是该地图仅显示西雅图的图像,而不是我保存在数据库中的标记。这是mapxml.html代码
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8"/>
<title>Google Maps AJAX + mySQL/PHP Example</title>
<script src="http://maps.google.com/maps/api/js?sensor=false"
type="text/javascript"></script>
<script type="text/javascript">
//<![CDATA[
var customIcons = {
field: {
icon: 'img/marker.png',
shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'
},
Park: {
icon: 'img/marker.png',
shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'
}
};
function load() {
var map = new google.maps.Map(document.getElementById("map"), {
center: new google.maps.LatLng(47.6145, -122.3418),
zoom: 13,
mapTypeId: 'roadmap'
});
var infoWindow = new google.maps.InfoWindow;
// Change this depending on the name of your PHP file
downloadUrl("phpsqlajax_genxml.php", function(data) {
var xml = data.responseXML;
var markers = xml.documentElement.getElementsByTagName("markers");
for (var i = 0; i < markers.length; i++) {
var name = markers[i].getAttribute("name");
var type = markers[i].getAttribute("type");
var point = new google.maps.LatLng(
parseFloat(markers[i].getAttribute("lat")),
parseFloat(markers[i].getAttribute("lng")));
var html = "<b>" + name + "</b> <br/>" + address;
var icon = customIcons[type] || {};
var marker = new google.maps.Marker({
map: map,
position: point,
icon: icon.icon,
shadow: icon.shadow
});
bindInfoWindow(marker, map, infoWindow, html);
}
});
}
function bindInfoWindow(marker, map, infoWindow, html) {
google.maps.event.addListener(marker, 'click', function() {
infoWindow.setContent(html);
infoWindow.open(map, marker);
});
}
function downloadUrl(url, callback) {
var request = window.ActiveXObject ?
new ActiveXObject('Microsoft.XMLHTTP') :
new XMLHttpRequest;
request.onreadystatechange = function() {
if (request.readyState == 4) {
request.onreadystatechange = doNothing;
callback(request, request.status);
}
};
request.open('GET', url, true);
request.send(null);
}
function doNothing() {}
//]]>
</script>
</head>
<body onload="load()">
<div id="map" style="width: 500px; height: 300px"></div>
</body>
</html>
有人知道我的标记没有显示的原因吗?
我一直在关注 Google 教程,并且我的 XML 输出正常,但是我似乎无法完成说明 https://developers.google.com/maps/articles/phpsqlajax_v3
如果有人能提供帮助,我将不胜感激!
【问题讨论】:
-
您是否尝试过使用静态坐标放置标记并忽略 xml 输出进行测试?
-
AJAX 请求返回的 XML 是什么样的?
标签: php mysql xml google-maps google-maps-api-3