ANDROID JSON 检索 json 数据的具体值答案

【问题标题】：ANDROID JSON Retrieve specific value of json dataANDROID JSON 检索 json 数据的具体值
【发布时间】：2016-09-03 06:31:01
【问题描述】：

我想检索administrative_area_level_1 值作为状态，locality 值作为区域，formatted_address 值作为地址以供进一步使用。我使用谷歌地图 api，我在其中给出纬度和经度，它将返回包含我想要的数据的 json 对象。

以下是我用来检索包含我想要的部分结果的数据的 url 示例。

http://maps.google.com/maps/api/geocode/json?latlng=1.56406166666667,103.626493333333&sensor=true

    {
       "results" : [
          {
             "address_components" : [
                {
                   "long_name" : "Jalan Cengal",
                   "short_name" : "Jalan Cengal",
                   "types" : [ "route" ]
                },
                {
                   "long_name" : "Johor Bahru",
                   "short_name" : "Johor Bahru",
                   "types" : [ "locality", "political" ]
                },
                {
                   "long_name" : "Johor",
                   "short_name" : "Johor",
                   "types" : [ "administrative_area_level_1", "political" ]
                },
                {
                   "long_name" : "Malaysia",
                   "short_name" : "MY",
                   "types" : [ "country", "political" ]
                },
                {
                   "long_name" : "80990",
                   "short_name" : "80990",
                   "types" : [ "postal_code" ]
                }
             ],
             "formatted_address" : "Jalan Cengal, 80990 Johor Bahru, Johor, Malaysia",
......

所以起初这是我检索我想要的数据的编码。

private void extractPosition(JSONObject json)
{
    JSONObject result = json.optJSONArray("results").optJSONObject(0);
    JSONArray address_components = result.optJSONArray("address_components");

    area.setText(address_components.optJSONObject(1).optString("short_name"));

    state.setText(address_components.optJSONObject(2).optString("short_name"));

    address.setText(result.optString("formatted_address"));
}

但后来我意识到位置并不总是相同，因为某些坐标具有如下所示的附加信息，因此我不能依赖数据的位置。

{
   "results" : [
      {
         "address_components" : [
            {
               "long_name" : "Jalan Kebudayaan 11",
               "short_name" : "Jalan Kebudayaan 11",
               "types" : [ "route" ]
            },
            {
               "long_name" : "Taman Universiti",
               "short_name" : "Taman Universiti",
               "types" : [ "sublocality_level_1", "sublocality", "political" ]
            },
            {
               "long_name" : "Skudai",
               "short_name" : "Skudai",
               "types" : [ "locality", "political" ]
            },
            {
               "long_name" : "Johor",
               "short_name" : "Johor",
               "types" : [ "administrative_area_level_1", "political" ]
            },
            {
               "long_name" : "Malaysia",
               "short_name" : "MY",
               "types" : [ "country", "political" ]
            },
            {
               "long_name" : "81300",
               "short_name" : "81300",
               "types" : [ "postal_code" ]
            }
         ],
         "formatted_address" : "Jalan Kebudayaan 11, Taman Universiti, 81300 Skudai, Johor, Malaysia",
.....

我应该如何修改我的编码以便检索administrative_area_level_1 和locality 值？

【问题讨论】：

标签： java android json google-maps-api-3

【解决方案1】：

private void extractPosition(JSONObject json)
{
    JSONObject result = json.optJSONArray("results").optJSONObject(0);
    JSONArray address_components = result.optJSONArray("address_components");

    for (int i =0; i<address_components.lenght;i++){

      if(address_components.optJSONObject(1).optString("short_name").equals("locality"))
        area.setText(address_components.optJSONObject(1).optString("short_name"));

      if (address_components.optJSONObject(1).optString("short_name").equals("administrative_area_level_1"))
        state.setText(address_components.optJSONObject(2).optString("short_name"));

      address.setText(result.optString("formatted_address"));
}
}

【讨论】：

【解决方案2】：

private void extractPosition(JSONObject json)
    {
        JSONObject result = json.optJSONArray("results").optJSONObject(0);
        JSONArray address_components = result.optJSONArray("address_components");

        for (int i =0; i<address_components.length();i++)
        {
            String searchKeyword;

            searchKeyword = address_components.optJSONObject(i).optString("types");
            Log.d("test", searchKeyword);

            if (searchKeyword.contains("locality"))
            {
                area.setText(address_components.optJSONObject(i).optString("short_name"));
            }

            if (searchKeyword.contains("administrative_area_level_1"))
            {
                state.setText(address_components.optJSONObject(i).optString("short_name"));
            }
        }

        address.setText(result.optString("formatted_address"));
    }

【讨论】：