如何序列化 json 以显示属性值而不是属性名称？

Question

我正在尝试找到一种将对象序列化为以下格式的json字符串的方法，以便我可以满足项目要求

{
  "id": 123456,
  "los": {
    "2019-05-13": [
      {
        "currency": "EUR",
        "guests": 2,
        "price": [
          100,
          200
        ]
      },
      {
        "currency": "EUR",
        "guests": 3,
        "price": [
          150,
          250
        ]
      }
    ],
    "2019-05-14": {
      "currency": "EUR",
      "guests": 2,
      "price": [
        300
      ]
    }
  },
}

我创建了这些模型类：

public class Rootobject
{
    public Los los { get; set; }
    public int Id { get; set; }
}

public class Los
{
    public Item[] items{ get; set; }
}

public class Item
{
    public DateTime date {get;set;}
    public string currency { get; set; }
    public int guests { get; set; }
    public int[] price { get; set; }
}

在序列化过程中可能会以某种方式更改元素的名称，因此 Item 被序列化为“2019-05-13”、“2019-05-14”等？

Answer 1

为此，您需要这个类结构：

public class Rootobject
{
    public int Id { get; set; }
    [JsonConverter(typeof(CustomItemConverter))]
    public Dictionary<DateTime, Item[]> Los { get; set; }
}

public class Item
{
    [JsonIgnore]
    public DateTime Date { get; set; }
    public string Currency { get; set; }
    public int Guests { get; set; }
    public int[] Price { get; set; }
}

和自定义转换器：

public class CustomItemConverter : JsonConverter
{
    public override bool CanRead => false;

    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(Dictionary<DateTime, Item[]>);
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        var dictionary = (Dictionary<DateTime, Item[]>)value;

        writer.WriteStartArray();
        foreach (var item in dictionary)
        {
            writer.WriteStartObject();
            writer.WritePropertyName(item.Key.Date.ToString("yyyy-MM-dd"));
            serializer.Serialize(writer, item.Value);
            writer.WriteEndObject();
        }
        writer.WriteEndArray();
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        throw new NotImplementedException("Unnecessary because CanRead is false. The type will skip the converter.");
    }
}