【发布时间】:2019-02-18 11:13:41
【问题描述】:
我的应用程序有一个具有属性 shopList 的对象公司。 shoplist 将在 void initState() 中从 firebase 数据库获取数据。
Company(name: 'Storm',
about: 'xxxxxxxxxxxx',
backdropPhoto: 'assets/hk.jpg',
shopList: [],
location: 'HK',
logo: 'assets/logo.png',
president: 'Grand Production House');
shoplist 应该有 5 个不同的商店,但我不知道为什么会有 5 个数据相同的商店。
代码:
class CompanyDetailsPage extends StatefulWidget {
CompanyDetailsPage(
{@required AnimationController controller, this.context})
: animation = new CompanyDetsIntroAnimation(controller);
final BuildContext context;
final CompanyDetsIntroAnimation animation;
@override
_CompanyDetailsPageState createState() => _CompanyDetailsPageState();
}
class _CompanyDetailsPageState extends State<CompanyDetailsPage> {
Shop shopItems;
Company storm = Company(
name: 'Storm',
about: 'xxxxxxxxxxxx',
backdropPhoto: 'assets/hk.jpg',
shopList: [],
location: 'HK',
logo: 'assets/logo.png',
president: 'Grand Production House');
DatabaseReference databaseReference = FirebaseDatabase.instance.reference();
@override
void initState() {
super.initState();
shopItems = Shop();
databaseReference.child('HK').once().then((DataSnapshot snapshot) {
Map uid = snapshot.value;
uid.forEach((k,v) {
Map shopMap = v['Shop'];
shopMap.forEach((sk,sv) {
shopItems.key = sk;
shopItems.shopName = sv["ShopName"];
shopItems.address = sv["ShopAddress"];
shopItems.tel = sv["ShopTel"];
shopItems.thumbnail = sv["Thumbnail"];
debugPrint(shopItems.address);
storm.shopList.add(shopItems);
debugPrint(shopItems.key);
});
});
for (int i = 0; i < storm.shopList.length; i++) {
debugPrint("Username: ${storm.shopList[i].address }, User Id: ${storm.shopList[i].key}");
}
});
}
控制台结果:
- 正在将文件同步到设备 iPhone X...
- 颤振:-LM3JFMq5y9fNVA431QW
- 颤振:-LMHR9YQFqgKlnFArwEN
- 颤振:-LM3JH8KMha3aeN-YEq5
- 颤振:-LM3JJTFda0c3qKaKEaL
- 颤动:-LMIaUIBOhj1k6pjj9eY
- 颤振:ShopAddress:bbbbbb,ShopKey:-LMIaUIBOhj1k6pjj9eY
- 颤振:ShopAddress:bbbbbb,ShopKey:-LMIaUIBOhj1k6pjj9eY
- 颤振:ShopAddress:bbbbbb,ShopKey:-LMIaUIBOhj1k6pjj9eY
- 颤振:ShopAddress:bbbbbb,ShopKey:-LMIaUIBOhj1k6pjj9eY
- 颤振:ShopAddress:bbbbbb,ShopKey:-LMIaUIBOhj1k6pjj9eY
【问题讨论】:
-
您应该尝试使用更具描述性的词语来命名变量。很难像这样跟随。如果你调试方法,你能看到firebase返回的五个不同的商店吗?
-
debugPrint(shopItems.address) 打印出 5 个不同的地址,然后我将这个 shopItem 放入 Company 对象的 shopList 数组中。但是我打印了 shopList 数组的元素,它表明所有的项目都是一样的。我找不到问题所在。