【发布时间】:2020-01-04 08:10:23
【问题描述】:
好的,伙计们,这是我的问题。
我有一个仅标准 Rails 5 API 设置。
我的用户控制器非常标准:
# frozen_string_literal: true
class UsersController < ApplicationController
before_action :set_user, only: %i[show update destroy]
# GET /users
def index
@users = User.all
render json: @users
end
# GET /users/1
def show
render json: @user
end
# POST /users
def create
@user = User.new(user_params)
if @user.save
render json: @user, status: :created, location: @user
UserNotifierMailer.send_signup_email(@user).deliver
else
render json: @user.errors, status: :unprocessable_entity
end
end
# PATCH/PUT /users/1
def update
if @user.update(user_params)
render json: @user
else
render json: @user.errors, status: :unprocessable_entity
end
end
# DELETE /users/1
def destroy
@user.destroy
end
private
# Use callbacks to share common setup or constraints between actions.
def set_user
@user = User.find(params[:id])
end
# Only allow a trusted parameter "white list" through.
def user_params
params.require(:user).permit(:username, :password, :email)
end
end
现在,当我从 Postman 向服务器发布数据时,它可以完美运行,并且可以很好地注册用户。
另一方面,我正在使用 Flutter 应用程序,并且正在尝试注册。
这是 Flutter 模型。
import 'dart:convert';
import 'package:http/http.dart' as http;
class HeadUser {
User _user;
HeadUser({User user}) {
this._user = user;
}
HeadUser.fromJson(Map<String, dynamic> json) {
_user = json['user'] != null ? new User.fromJson(json['user']) : null;
}
Map<String, dynamic> toJson() {
final Map<String, dynamic> data = new Map<String, dynamic>();
if (this._user != null) {
data['user'] = this._user.toJson();
}
return data;
}
}
class User {
String _username;
String _email;
String _password;
int _id;
DateTime _createdAt;
DateTime _updatedAt;
User({int id, DateTime createdAt, DateTime updatedAt, String username, String email, String password}) {
this._username = username;
this._email = email;
this._password = password;
this._id = id;
this._createdAt = createdAt;
this._updatedAt = updatedAt;
}
factory User.fromJson(Map<String, dynamic> json) {
return User(
id: json['id'],
username: json['username'],
email: json['email'],
createdAt: json['created_at'],
updatedAt: json['updated_at'],
);
}
Map<String, dynamic> toJson() {
final Map<String, dynamic> data = new Map<String, dynamic>();
data['username'] = this._username;
data['email'] = this._email;
data['password'] = this._password;
return data;
}
}
Future<HeadUser> loginUser(String url, {Map body}) async {
return http.post(url, body: body).then((http.Response response) {
final int statusCode = response.statusCode;
if (statusCode < 200 || statusCode > 400 || statusCode == null) {
throw new Exception("Error while posting data");
}
return HeadUser.fromJson(json.decode(response.body));
});
}
我对这个的要求如下:
onPressed: () async {
if (_formKey.currentState.validate())
{
HeadUser usr = new HeadUser(user: User(
email: this.emailEditingController.text.trim(),
password: this.passwordEditingController.text.trim(),
username: this.usernameEditingController.text.trim()
));
HeadUser response = await loginUser(REGISTRATION_URL, body: usr.toJson());
但是当我这样做时,我的 Flutter 应用程序中出现错误,就像我缺少“用户”参数一样,虽然当我打印出来时它显示了确切的结构,但我明白了。
在这种情况下,请求甚至不会被触发,因此服务器不会受到攻击。
但是,如果我尝试在 loginUser 方法中执行 json.encode(body),那么我来自服务器的响应是:
当然,Flutter 也会抱怨:
我在这里做错了什么?
【问题讨论】:
-
Rails 接收的参数必须是
{ user: { id: ..., name: ... } }的形式,你现在发送的可能是{ id: ..., name: ... }。 -
@SebastianPalma 谢谢你的提示。这不是问题,而是请求标头。
标签: ruby-on-rails json flutter dart ruby-on-rails-5.2