Rails 4 销毁动作，未定义方法 message_path

Question

我对 Rails 销毁操作有疑问。我有完整的消息系统。用户可以发送、阅读消息但不能删除它。 我的消息控制器是：

class MessagesController < ApplicationController
 before_filter :set_user
 def index
   if params[:mailbox] == "sent"
    @messages = @user.sent_messages.page(params[:page])
   elsif params[:mailbox] == "inbox"
    @messages = @user.received_messages.page(params[:page])
   end
 end

 def new
  @message = Message.new
  @reply_to = User.find_by_id(params[:reply_to])
  unless @reply_to.nil?
    @message.recepient_id = @reply_to.id
  end
 end

 def create
  @message = Message.new(message_params)
  @message.sender_id = @user.id
  if @message.save
   flash[:notice] = "Message has been sent"
   redirect_to user_messages_path(current_user, :mailbox=>:inbox)
  else
   render :action => :new
  end
 end

 def show
  @message = Message.readingmessage(params[:id],@user.id)
 end
 def destroy
  @message = Message.find(params[:id])
  @message.destroy
 end

private

 def message_params
  params.require(:message).permit(:sender_id, :recepient_id, :body, :subject, :read_at)
 end

 def set_user
  @user = current_user
 end
end

我的路线是：

resources :users do
  resources :messages 
end

鉴于我有删除链接（不起作用）：

 %h2 Your Inbox
- if @messages.size == 0
  %h1 No messages in your Inbox
- else
  %table.table.table-bordered
    %tr
      %th Subject
      %th Sender
      %th Sent At
    - for message in @messages
      %tr
        %td
          - if message.read?
            = link_to h(message.subject), user_message_path(@user, message)
          - else
            = link_to "#{h(message.subject)} (unread)", user_message_path(@user, message)
        %td= "#{message.sender.name}"
        = link_to "Delete Message", @message, method: :delete, data: {confirm: "You sure?"}

当我点击此链接时，出现以下错误：

No route matches [DELETE] 

消息路由：

         user_messages GET    /users/:user_id/messages(.:format)          messages#index
                       POST   /users/:user_id/messages(.:format)          messages#create
      new_user_message GET    /users/:user_id/messages/new(.:format)      messages#new
     edit_user_message GET    /users/:user_id/messages/:id/edit(.:format) messages#edit
          user_message GET    /users/:user_id/messages/:id(.:format)      messages#show
                       PATCH  /users/:user_id/messages/:id(.:format)      messages#update
                       PUT    /users/:user_id/messages/:id(.:format)      messages#update
                       DELETE /users/:user_id/messages/:id(.:format)      messages#destroy

有什么想法吗？ :)

Answer 1

这是因为您在路由文件中使用嵌套路由来处理消息：

它将生成与用户关联的路由。所以要么改变你的链接路径

= link_to "Delete Message", user_message_path(message.user, message), method: :delete, data: {confirm: "You sure?"}

或者，

如果要删除没有用户对象的消息，请为消息定义单独的路由：

resources :messages 

现在，您将能够单独使用消息路由：

= link_to "Delete Message", message, method: :delete, data: {confirm: "You sure?"}

Answer 2

作为它的嵌套路径，你还需要传递用户对象..

= link_to "Delete Message", user_message_path(@message.user,@message), method: :delete, data: {confirm: "You sure?"}

Answer 3

因为你使用了嵌套路由，你需要在link_to中传递两个参数，即用户实例和消息实例。并显式编写命名路由。

像这样：

= link_to "Delete Message", user_message_path(@user, @message), \
  method: :delete, data: {confirm: "You sure?"}