Java JsonPath - 获取原始类型属性的所有路径

Question

我想从属性类型为原始（不是对象或数组）的 json 文件中查找所有 Json 路径

考虑 jsonString：

{
   "header": {
       "version": 2,
       "original": "ori",
       "parent": "par",
       "eventId": 11,
       "correlation": "uuid",
       "timestamp": "03.04.2020",
       "local": true,
       "location": {
           "facility": {
               "id": 3,
               "type": "en"
           }
       }
   },
   "body": {
       "field": 3
   }
} 

我使用以下代码：

Configuration configuration = Configuration.builder().options(Option.AS_PATH_LIST).build();
List<String> paths = JsonPath.using(configuration).parse(jsonString).read("$..*");

实际结果： 模式 "$..*" 向我返回 json 中存在的所有路径：

• $['header']
• $['body']
• $['header']['version']
• $['header']['original']
• $['header']['parent']
• $['header']['eventId']
• $['header']['correlation']
• $['header']['timestamp']
• $['header']['local']
• $['header']['location']
• $['header']['location']['facility']
• $['header']['location']['facility']['id']
• $['header']['location']['facility']['type']
• $['body']['field']

预期结果：我只需要得到这些：

• $['header']['version']
• $['header']['original']
• $['header']['parent']
• $['header']['eventId']
• $['header']['correlation']
• $['header']['timestamp']
• $['header']['local']
• $['header']['location']['facility']['id']
• $['header']['location']['facility']['type']
• $['body']['field']

过滤器应该是通用的，因此它可以解析作为输入给出的任何 json 格式。

Answer 1

您可以使用下面的 JSONPath，它将给出包含对象或数组的路径，然后您可以将其从 JSONPath 的整个列表中排除。

JSONPath

$..*[?(@.length != 0)]

Java 代码

List<String> allPaths = JsonPath.using(configuration).parse(jsonString).read("$..*");
List<String> exludedPaths = JsonPath.using(configuration).parse(jsonString).read("$..*[?(@.length != 0)]");
List<String> primitivePaths = allPaths.removeAll(exludedPaths);