【发布时间】:2020-06-27 22:13:26
【问题描述】:
每个人。在这里,我有一个六进制到二进制和十进制转换器。问题是当我输入无效输入(例如字母 G 或 X)时,它会给我一个负输出。我怎样才能阻止它这样做,而是打印出它是一个无效的数字
public static int hex2decimal(String s)
{
String digits = "0123456789ABCDEF";
s = s.toUpperCase();
int val = 0;
for (int i = 0; i < s.length(); i++)
{
char c = s.charAt(i);
int d = digits.indexOf(c);
val = 16*val + d;
}
return val;
}
public static void main(String args[])
{
String hexdecnum;
int decnum, i=1, j;
int binnum[] = new int[100];
Scanner scan = new Scanner(System.in);
System.out.print("Enter Hexadecimal Number : ");
hexdecnum = scan.nextLine();
final int MAX_LENGTH = 2;
if(String.valueOf(hexdecnum).length() <= MAX_LENGTH) {
/* first convert the hexadecimal to decimal */
decnum = hex2decimal(hexdecnum);
System.out.print("Equivalent Dec Number is : "+ decnum);
System.out.println();
/* now convert the decimal to binary */
while(decnum != 0)
{
binnum[i++] = decnum%2;
decnum = decnum/2;
}
System.out.print("Equivalent Binary Number is : ");
for(j=i-1; j>0; j--)
{
System.out.print(binnum[j]);
}
} else {
System.out.println("ERROR: Invalid Input");
System.out.print("Enter a number: ");
}
}
【问题讨论】:
-
你能检查一下输入是否只包含 A-F 吗?