我可以用逗号将多行分隔为一列吗？ [复制]

Question

我正在尝试在我的 SQL Server 数据库中合并类似的内容：

[TicketID], [Person]
 T0001 爱丽丝
 T0001 鲍勃
 T0002 凯瑟琳
 T0002 道格
 T0003 伊莱恩

进入这个：

[TicketID]、[人物]
 T0001 爱丽丝，鲍勃
 T0002 凯瑟琳，道格
 T0003 伊莱恩

我需要在 SQL Server 和 Oracle 中都这样做。

我找到了用于 MySQL 的函数 GROUP_CONCAT，它完全可以满足我的需要，但这里不能选择 MySQL。

编辑：测试台：

DECLARE @Tickets TABLE (
    [TicketID] char(5) NOT NULL,
    [Person] nvarchar(15) NOT NULL
)

INSERT INTO @Tickets VALUES
    ('T0001', 'Alice'),
    ('T0001', 'Bob'),
    ('T0002', 'Catherine'),
    ('T0002', 'Doug'),
    ('T0003', 'Elaine')

SELECT * FROM @Tickets

Answer 1

我已经找到了在 Oracle 中执行此操作的方法，但我仍需要在 SQL Server 中执行此操作。

来自http://technology.amis.nl/blog/6118/oracle-rdbms-11gr2-listagg-new-aggregation-operator-for-creating-comma-delimited-strings （感谢tanging）（ORACLE 11 及更高版本）

select
    TicketId,
    listagg(Person, ', ') People
from
    table
group by
    TicketId

发件人：http://halisway.blogspot.com/2006/08/oracle-groupconcat-updated-again.html

with
    data
as
  (
    select
        TicketId,
        Person,
        ROW_NUMBER() over (partition by TicketId order by Person) "rownum",
        COUNT(*) over (partition by TicketId) "count"
    from
        Table
  )
select
    TicketId,
    LTRIM(sys_connect_by_path(Person,','),',') People
from
    data
where
    "rownum" = "count"
start with
    "rownum" = 1
connect by
    prior TicketId = TicketId
  and
    prior "rownum" = "rownum" - 1
order by
    TicketId

Answer 2

这是一个适用于 SQL Server 2005+ 的解决方案：

SELECT t.TicketID,
       STUFF(ISNULL((SELECT ', ' + x.Person
                FROM @Tickets x
               WHERE x.TicketID = t.TicketID
            GROUP BY x.Person
             FOR XML PATH (''), TYPE).value('.','VARCHAR(max)'), ''), 1, 2, '') [No Preceeding Comma],
       ISNULL((SELECT ', ' + x.Person
                FROM @Tickets x
               WHERE x.TicketID = t.TicketID
            GROUP BY x.Person
             FOR XML PATH (''), TYPE).value('.','VARCHAR(max)'), '') [Preceeding Comma If Not Empty]
  FROM @Tickets t
GROUP BY t.TicketID

参考：

• STUFF (Transact-SQL)

Answer 3

为了完整起见，还有 MySQL 版本：

select
    TicketId,
    GROUP_CONCAT(Person ORDER BY Person SEPARATOR ', ') People
from
    table
group by
    TicketId

Answer 4

一个例子

SELECT DISTINCT
    t.TicketID,
    STUFF((SELECT ', ', i.Person as [text()]
           FROM @Tickets i 
           WHERE i.TicketID = t.TicketID
           FOR XML PATH ('')), 1, 2, '') as People
FROM
    @Tickets t

............或尝试............

SELECT DISTINCT
    t.TicketID,
    STUFF((SELECT ', ' + i.Person    /* notice this line is different */
           FROM @Tickets i 
           WHERE i.TicketID = t.TicketID
           FOR XML PATH ('')), 1, 2, '') as People
FROM
    @Tickets t

/* 当我将它用于我的桌子时，这很有效，并且归功于我的经理，ROCKS！ */

Answer 5

DECLARE @Tickets TABLE (
    [TicketID] char(5) NOT NULL,
    [Person] nvarchar(15) NOT NULL
)
INSERT INTO @Tickets VALUES
    ('T0001', 'Alice'),
    ('T0001', 'Bob'),
    ('T0002', 'Catherine'),
    ('T0002', 'Doug'),
    ('T0003', 'Elaine')

SELECT * FROM @Tickets

Select [TicketID],
STUFF((SELECT ',' + Person FROM @Tickets WHERE (
TicketID=Result.TicketID) FOR XML PATH ('')),1,1,'') AS BATCHNOLIST
From @Tickets AS Result
GROUP BY TicketID