【发布时间】:2013-12-15 15:15:04
【问题描述】:
我正在尝试使用 CGridView 显示结果。我有两个表 Users 和 products。 ExiProducts 是维护多对多关系的表,然后让关系名称为'myrelation'
public function actionSearch() {
if(isset($_GET['searchButton'] && $_GET['searchType']==='products') {
$searchString= trim(strip_tags($_GET['searchValue']));
$model=new Products;
$criteria->compare('productName', $searchString, TRUE, 'AND', TRUE);
$criteria->compare('productType',$searchString,true,'OR',TRUE);
$criteria->compare('productBrand',$searchString,true,'OR',TRUE);
$criteria->compare('description',$searchString,true,'OR',true);
$dataProviderObj=new CActiveDataProvider($model, array(
'criteria'=>$criteria,
));
}
$this->render('search',array(
'dataProviderObj'=>$dataProviderObj,
'model'=>$model,
));
}
这是我的view.php
$this->widget('zii.widgets.grid.CGridView', array(
'id'=>'users-grid',
'dataProvider'=>$dataProviderObj,
'columns'=>array(
'productName',
'productType',
'productBrand',
'description',
'I WANT THE NAME OF EVERY USER THAT CREATED THIS PRODUCT
HERE WHICH IS IN THE USERS TABLE '
),
));
谁能告诉我如何获得在那里创建这些产品的用户的名称。 users 表中的列是
UserId,
Username
和ExiProducts是
UserId,
ProductId
更新了我的代码
public function gridCreateUser($data,$row) {
$myproducts=array();
$user = $data->userId;
$records= Users::model()->with('usersproducts')->findAll('userId=:userId',array(':userId'=>$user));
foreach($records as $record)
{
foreach($record->usersproducts as $productis)
{
$myproducts[]=$productis->productName;
}
}
return $myproducts;
}
【问题讨论】: