在不使用列表框绑定的情况下从 Tkinter 列表框中获取所选项目

Question

我有 2 个列表框（连接起来以便项目可以从一个移动到另一个），最后我想通过使用“确定”按钮（或简单地关闭框架）。每次选择一个项目时，我都可以向列表添加/删除值（如下面代码的注释部分所示），但我宁愿在 close 函数中使用一行代码沿 [master.selected.get(idx) for idx in master.selected.curselection()] 行但我无法让它工作。

代码：

def measurementPopup(self,master):
    self.chargeCarrier = StringVar()
    self.massModifiers = StringVar()
    self.chargeCarrier.set("[M+xH]")

    def onselect1(evt):
        w = evt.widget
        index = int(w.curselection()[0])
        value = w.get(index)
        # My Dirty fix -> Here I could enter the selected value to a buffer list (to be returned in the ok function).
        master.selected.insert(END,value)
        master.avail.delete(index)

    def onselect2(evt):
        w = evt.widget
        index = int(w.curselection()[0])
        value = w.get(index)
        # My Dirty fix -> Here I could remove the selected value from a buffer list (to be returned in the ok function).
        master.selected.delete(index)
        master.avail.insert(END,value)

    def close(self):
        # Here I would return the buffer list and close the window
        master.measurementWindow = 0
        top.destroy()

    if master.measurementWindow == 1:
        return

    master.measurementWindow = 1
    top = self.top = Toplevel()
    top.protocol( "WM_DELETE_WINDOW", lambda: close(self))
    self.charge = Label(top, text = "Charge", width = 10)
    self.charge.grid(row = 0, column = 0, sticky = W)
    self.min = Label(top, text = "Min", width = 5)
    self.min.grid(row=0, column = 1, sticky = W)
    self.minCharge = Spinbox(top, from_= 1, to = 3, width = 5)
    self.minCharge.grid(row = 0, column = 2, sticky = W)
    self.max = Label(top, text = "Max", width = 5)
    self.max.grid(row = 0, column = 3, sticky = W)                  
    self.maxCharge = Spinbox(top, from_ = 1, to=3, width=5)
    self.maxCharge.grid(row = 0, column = 4, sticky = W)
    self.chargeCarrier = OptionMenu(top, self.chargeCarrier, "[M+xH]", "[M+xNa]")
    self.chargeCarrier.grid(row = 0, column = 5, sticky = W)
    self.availMass = Label(top, text = "Available")
    self.availMass.grid(row = 1, column = 1, sticky = W)
    self.selectMass = Label(top, text = "Selected")
    self.selectMass.grid(row = 1, column = 3, sticky = W)
    self.massMod = Label(top, text = "Mass Mods")
    self.massMod.grid(row = 2, column = 0, sticky = W)
    self.avail = Listbox(top)
    for i in UNITS:
        if BLOCKS[i]['available'] == 1:
            self.avail.insert(END,BLOCKS[i]['human_readable_name'])
    self.avail.grid(row = 2, column = 1, columnspan = 2, sticky = W)
    self.avail.bind('<<ListboxSelect>>',onselect1)
    self.selected = Listbox(top)
    self.selected.grid(row = 2, column = 3, columnspan = 2, sticky = W)
    self.selected.bind('<<ListboxSelect>>',onselect2)
    self.ok = Button(top,text = 'Ok',command = lambda: close(self))
    self.ok.grid(row = 3, column = 0, sticky = W)

我曾尝试在close函数中使用如下小sn-p：

        values = [master.selected.get(idx) for idx in master.selected.curselection()]
        print ', '.join(values)

但是，for 段不返回任何内容。我预计这是因为实际上没有选择任何内容，但我需要一些相反的东西，沿着 master.selected.allitems() 的路线（如果它存在并且我理解正确的话）。

总结

如何获得 1 个特定列表框中的所有项目？

Answer 1

Listbox 小部件的.get() 函数允许您指定一系列项目，可以将其指定为0 到END 以返回所有项目的元组。

例子：

from Tkinter import *
root = Tk()
l = Listbox(root, width = 15)
l.pack()
l.insert(END, "Hello")
l.insert(END, "world")
l.insert(END, "here")
l.insert(END, "is")
l.insert(END, "an")
l.insert(END, "example")

def close():
    global l, root
    items = l.get(0, END)
    print(items)
    root.destroy()

b = Button(root, text = "OK", command = close).pack()
root.mainloop()

我希望这会有所帮助，如果这不是您想要的，请在评论中告诉我，我可以尝试扩展我的答案。