为什么我不能用这个表单将数据插入我的数据库？

Question

我尝试了几个我在互联网上遇到的代码，但我无法达到我的目标，即创建一个具有 3 个下拉列表的表单，然后将插入的数据输入到 SQL 表中。

我的代码没有按预期工作，两周以来我一直在努力解决这个问题。因此，我将不胜感激任何减轻这种情况的帮助。

<?php
$ligacao = new mysqli("localhost", "root", "", "pap");
if ($ligacao->connect_errno == 0) {
    if (isset($_POST['submit'])) {
        $instic = $conn->query("INSERT INTO tickets(problema, eletrecidade, agua, assunto, info) VALUES('" . $_POST["prob"] . "', '" . $_POST["elet"] . "','" . $_POST["agua"] . "','" . $_POST["ass"] . "','" . $_POST["info"] . "')");
        $instic->bind_param("sssss", $_POST["prob"], $_POST["elet"], $_POST["agua"], $_POST["ass"], $_POST["info"]);
        $instic->execute();
    }
}
$ligacao->close();
?>

<form method="POST" action="inserir.php" enctype="multipart/form-data">
    <fieldset>
        <!-- Escolher problema geral -->
        <label>Problema Geral</label>
        <select name="prob">
            <option disabled selected hidden>Escolha uma opção...</option>
            <option name="luz" value="Luz">Luz</option>
            <option name="agua" value="Agua">Agua</option>
            <option name="ele" value="Elevador">Elevador</option>
        </select>

        <!-- Escolher problemas eletrecidade -->
        <label>Eletrecidade</label>
        <select name="elet" id="elet">
            <option disabled selected hidden>Escolha uma opção...</option>
            <option name="semluz" value="Nao ha luz">Não há luz</option>
            <option name="curto" value="Curto Circuito">Curto circuito</option>
        </select>

        <!-- Escolher problemas agua -->
        <label>Agua</label>
        <select name="agua" id="agua">
            <option disabled selected hidden>Escolha uma opção...</option>
            <option name="semagua" value="Nao ha agua">Não há água</option>
            <option name="inund" value="Inundacao">Inundação</option>
        </select>
        <label for="assunto">Assunto:</label>
        <input type="text" name="ass" id="ass" maxlength=100 placeholder="Assunto">
    </fieldset>

    <fieldset>
        <label for="info">Info:</label>
        <textarea type="text" name="info" id="info" maxlength=50 placeholder="Descrição detalhada"></textarea>
    </fieldset>

    <div>
        <input type="reset" value="Limpar">
        <input type="submit" value="Submeter">
    </div>
</form>

Answer 1

在inserir.php文件中：

创建与您的数据库的连接

$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";


$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

使用 $_POST 获取表单数据

$prob = $_POST['prob'];
$elet = $_POST['elet'];
$agua = $_POST['agua'];
$ass  = $_POST['ass'];
$info = $_POST['info'];

并使用 sql 语句插入

$sql = "INSERT INTO tickets(problema, eletrecidade, agua, assunto, info) VALUES('$prob','$elet','$agua','$ass','$info')";

确保字符串值使用 ' ' 而整数不使用。并执行命令。

if ($conn->query($sql) === TRUE) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . $conn->error;
}

$conn->close();
?>

阅读更多：https://www.w3schools.com/php/php_mysql_insert.asp