【发布时间】:2019-06-06 19:58:33
【问题描述】:
我已经实现了以下装饰器:
class alias(object):
"""
A decorator for implementing method aliases.
"""
def __init__(self, *aliases):
self.aliases = set(aliases)
def __call__(self, obj):
if type(obj) == property:
obj.fget._aliases = self.aliases
else:
obj._aliases = self.aliases
return obj
def aliased(aliased_class):
"""
A decorator for enabling method aliases.
"""
aliased_class_dict = aliased_class.__dict__.copy()
aliased_class_set = set(aliased_class_dict)
for name, method in aliased_class_dict.items():
aliases = None
if (type(method) == property) and hasattr(method.fget, '_aliases'):
aliases = method.fget._aliases
elif hasattr(method, '_aliases'):
aliases = method._aliases
if aliases:
for a in aliases - aliased_class_set:
setattr(aliased_class, a, method)
return aliased_class
下面是我如何使用它们来创建属性和方法的可调用别名的示例:
@aliased
class MyClass(object):
@alias('a')
@property
def alpha(self) -> float:
"""
Returns the value of alpha.
"""
return 2.5
@alias('agt')
def alpha_greater_than(value) -> bool:
"""
Checks whether alpha is greater than the given value.
"""
return self.alpha > value
mc = MyClass()
result = mc.agt(3.0)
# ...
现在我正在打包我的项目并构建文档。目前,别名方法和属性“继承”原始实体的相同文档字符串。我想知道是否可以在装饰器级别操作别名实体的文档字符串,使它们看起来像:
此方法/属性是 X 的别名。
【问题讨论】:
标签: python python-3.x decorator alias docstring