【发布时间】：2011-07-08 03:12:15
【问题描述】：
我正在使用 Spring 的 @ExceptionHandler 注释在我的控制器中捕获异常。
一些请求将 POST 数据保存为写入请求正文的纯 XML 字符串，我想读取该数据以记录异常。 问题是当我在异常处理程序中请求输入流并尝试从中读取时，流返回-1（空）。
异常处理程序签名是：
@ExceptionHandler(Throwable.class)
public ModelAndView exception(HttpServletRequest request, HttpServletResponse response, HttpSession session, Throwable arff)
有什么想法吗？有没有办法访问请求正文？
我的控制器：
@Controller
@RequestMapping("/user/**")
public class UserController {
static final Logger LOG = LoggerFactory.getLogger(UserController.class);
@Autowired
IUserService userService;
@RequestMapping("/user")
public ModelAndView getCurrent() {
return new ModelAndView("user","response", userService.getCurrent());
}
@RequestMapping("/user/firstLogin")
public ModelAndView firstLogin(HttpSession session) {
userService.logUser(session.getId());
userService.setOriginalAuthority();
return new ModelAndView("user","response", userService.getCurrent());
}
@RequestMapping("/user/login/failure")
public ModelAndView loginFailed() {
LOG.debug("loginFailed()");
Status status = new Status(-1,"Bad login");
return new ModelAndView("/user/login/failure", "response",status);
}
@RequestMapping("/user/login/unauthorized")
public ModelAndView unauthorized() {
LOG.debug("unauthorized()");
Status status = new Status(-1,"Unauthorized.Please login first.");
return new ModelAndView("/user/login/unauthorized","response",status);
}
@RequestMapping("/user/logout/success")
public ModelAndView logoutSuccess() {
LOG.debug("logout()");
Status status = new Status(0,"Successful logout");
return new ModelAndView("/user/logout/success", "response",status);
}
@RequestMapping(value = "/user/{id}", method = RequestMethod.POST)
public ModelAndView create(@RequestBody UserDTO userDTO, @PathVariable("id") Long id) {
return new ModelAndView("user", "response", userService.create(userDTO, id));
}
@RequestMapping(value = "/user/{id}", method = RequestMethod.GET)
public ModelAndView getUserById(@PathVariable("id") Long id) {
return new ModelAndView("user", "response", userService.getUserById(id));
}
@RequestMapping(value = "/user/update/{id}", method = RequestMethod.POST)
public ModelAndView update(@RequestBody UserDTO userDTO, @PathVariable("id") Long id) {
return new ModelAndView("user", "response", userService.update(userDTO, id));
}
@RequestMapping(value = "/user/all", method = RequestMethod.GET)
public ModelAndView list() {
return new ModelAndView("user", "response", userService.list());
}
@RequestMapping(value = "/user/allowedAccounts", method = RequestMethod.GET)
public ModelAndView getAllowedAccounts() {
return new ModelAndView("user", "response", userService.getAllowedAccounts());
}
@RequestMapping(value = "/user/changeAccount/{accountId}", method = RequestMethod.GET)
public ModelAndView changeAccount(@PathVariable("accountId") Long accountId) {
Status st = userService.changeAccount(accountId);
if (st.code != -1) {
return getCurrent();
}
else {
return new ModelAndView("user", "response", st);
}
}
/*
@RequestMapping(value = "/user/logout", method = RequestMethod.GET)
public void perLogout(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
userService.setOriginalAuthority();
response.sendRedirect("/marketplace/user/logout/spring");
}
*/
@ExceptionHandler(Throwable.class)
public ModelAndView exception(HttpServletRequest request, HttpServletResponse response, HttpSession session, Throwable arff) {
Status st = new Status();
try {
Writer writer = new StringWriter();
byte[] buffer = new byte[1024];
//Reader reader2 = new BufferedReader(new InputStreamReader(request.getInputStream()));
InputStream reader = request.getInputStream();
int n;
while ((n = reader.read(buffer)) != -1) {
writer.toString();
}
String retval = writer.toString();
retval = "";
} catch (IOException e) {
e.printStackTrace();
}
return new ModelAndView("profile", "response", st);
}
}
谢谢
【问题讨论】：
标签： java spring spring-mvc exceptionhandler