【发布时间】:2016-01-06 00:36:37
【问题描述】:
我创建了一个选项卡式面板和手风琴式面板。我想将每个选项卡链接到每个手风琴,以便在选择(或打开)选项卡时选择相应的手风琴,反之亦然。我不太确定我是否使用了正确的组件来获得这种效果。请看下面的代码和截图:
代码:
<af:form id="f1">
<af:panelSplitter orientation="vertical" splitterPosition="121" id="ps3">
<f:facet name="first">
</f:facet>
<f:facet name="second">
<af:decorativeBox theme="dark" id="db3">
<f:facet name="center">
<af:decorativeBox theme="medium" id="db1">
<f:facet name="center">
<af:panelSplitter orientation="horizontal" splitterPosition="201" id="ps1">
<f:facet name="first">
<af:panelAccordion discloseMany="true" id="pa1">
<af:showDetailItem id="pane1" text="A"/>
<af:showDetailItem id="pane2" text="B"/>
<af:showDetailItem id="pane3" text="C"/>
</af:panelAccordion>
</f:facet>
<f:facet name="second">
<af:panelSplitter orientation="horizontal" splitterPosition="225"
positionedFromEnd="true" id="ps2">
<f:facet name="first">
<af:decorativeBox theme="default" id="db2">
<f:facet name="center">
<af:panelSplitter id="ps4" orientation="vertical"
splitterPosition="600">
<f:facet name="first">
<af:panelTabbed position="above" id="pt2">
<af:showDetailItem id="tab2"
text="A"
disclosed="true">
<af:panelDashboard id="pd2"
inlineStyle="width:600px;"
dimensionsFrom="parent"/>
</af:showDetailItem>
<af:showDetailItem text="B"
id="sdi3"/>
<af:showDetailItem text="C"
id="sdi4"/>
</af:panelTabbed>
</f:facet>
<f:facet name="second">
<af:panelTabbed position="above" id="pt1"/>
</f:facet>
</af:panelSplitter>
</f:facet>
</af:decorativeBox>
</f:facet>
<f:facet name="second">
</f:facet>
</af:panelSplitter>
</f:facet>
</af:panelSplitter>
</f:facet>
</af:decorativeBox>
</f:facet>
</af:decorativeBox>
</f:facet>
</af:panelSplitter>
</af:form>
【问题讨论】:
-
我一周前用代码解决方案回答了这个问题,但如果它有帮助,则看不到任何回应或投票,这是应该的。如果您不放弃投票,我将停止回答您的问题。
标签: jsp jsf accordion oracle-adf