【发布时间】:2023-04-08 00:52:02
【问题描述】:
我正在使用 Firebase 分析。我注册了两个用户属性,我有两个自定义事件,每个事件包含 3 到 50 个不同的选项选项。我遇到的问题是,当我设置用户属性时,DebugView 经常显示事件的旧用户属性或根本不显示。有时它可以正常工作。请告诉我如何解决?
我的代码。
final class FirebaseAnalyticsManager {
enum ScreenType {
case editStoryScreen, homeScreen, previewStoryScreen, storeItemPreviewScreen
var name: String {
switch self {
case .editStoryScreen:
return "Edit Story Screen"
case .homeScreen:
return "Home Screen"
case .previewStoryScreen:
return "Preview Story Screen"
case .storeItemPreviewScreen:
return "Store Item Preview Screen"
}
}
}
enum Event {
case templateSelected, mediaExport
var name: String {
switch self {
case .templateSelected:
return "TemplateSelected"
case .mediaExport:
return "MediaExport"
}
}
}
enum MediaExportDestination {
case story, page, pageToInstagram
var name: String {
switch self {
case .story:
return "Story"
case .page:
return "Page"
case .pageToInstagram:
return "PageToInstagram"
}
}
}
private enum Keys: String {
case exportType, templateName
}
private init() { }
static let shared = FirebaseAnalyticsManager()
open func trackScreen(_ screenType: ScreenType, screenClass: String?) {
Analytics.setScreenName(screenType.name, screenClass: screenClass)
}
private func trackEvent(_ event: Event, parameters: [String : NSObject]?) {
Analytics.logEvent(event.name, parameters: parameters)
}
open func trackTemplateSelected(_ templateName: String) {
let key = Keys.templateName.rawValue
Analytics.setUserProperty(templateName, forName: key)
var parameters = [String : NSObject]()
parameters[key] = templateName as NSObject
trackEvent(.templateSelected, parameters: parameters)
}
open func trackMediaExport(_ destination: MediaExportDestination) {
let key = Keys.exportType.rawValue
Analytics.setUserProperty(destination.name, forName: key)
var parameters = [String : NSObject]()
parameters[key] = destination.name as NSObject
trackEvent(.mediaExport, parameters: parameters)
}
}
【问题讨论】:
标签: ios swift firebase firebase-analytics firebase-console