【发布时间】:2015-08-19 22:18:17
【问题描述】:
我想传递一个方法(SaveClound)作为参数(AlertDialog Parameter),所以我可以通过这个参数使用不同的方法(在actionButtons方法中)。
public void actionButtons(){
buttonVoltar.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
alertDialog(saveClound());
// see? I want to call the a method through this parameter
}
});
}
public void alertDialog(Method methodName) {
AlertDialog.Builder builderaction = new AlertDialog.Builder(this);
builderaction.setTitle("Atenção!");
builderaction.setMessage("Você tem certeza que deseja sair?");
builderaction.setPositiveButton("Yes",new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
// i want to call here the paramater i'm passing on this method (methodName)
// so i can call any methods i want right here
}
});
builderaction.setNegativeButton("No",new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
dialog.dismiss();
}
});
AlertDialog alert = builderaction.create();
alert.setIcon(R.drawable.ic_stop);
alert.show();
}
public void saveClound(){
Toast.makeText(getApplicationContext(), "ABC", Toast.LENGTH_SHORT).show();
}
【问题讨论】:
-
如果您尝试将方法作为参数传递,那么在 Java 中是不可能的。有很多方法可以通过接口来做到这一点。检查这个 SO 问题。 stackoverflow.com/questions/2186931/…
-
我看到了,但我看不懂.. :/
-
查看我的answer
标签: android methods parameters