Ruby - 将 rails 的“业务逻辑”移动到服务模块中

Question

我想按照正确的 OOP 协议将一些 Rails 业务逻辑移动到服务中。我按照这里推荐的方法：Private module methods in Ruby

最终，我想将业务逻辑从模型和控制器转移到服务中，这些服务是普通的旧 Ruby 对象。因此，模型只关心持久性、范围和验证。

这是制作服务模块的正确方法吗？

版本 2：

module CategorizeJobs

  def self.fetch( location, category_name )
    c = Categorizer.new( location, category_name )
    c.get_jobs
  end

  class Categorizer

    def initialize(location, category_name)
      @location = location
      @category_name = category_name
    end

    def get_jobs
      job_ids = get_correct_jobs
      Category.includes(:jobs).where( jobs: { id:  job_ids } )
    end

    private

      def get_correct_jobs
        jobs = filter_by_location
        jobs = filter_by_category(jobs)

        jobs.collect(&:id)
      end

      def filter_by_category(jobs)
        return jobs unless @category_name.present?

        category = Category.where(name: @category_name).first
        if category
          jobs = jobs.where(category: category)
        end

        jobs
      end

      def filter_by_location
        if @location.present?
          jobs = get_jobs_at_location
        else
          jobs = Job.open
        end
      end

      def get_jobs_at_location(location)
        Job.joins(:location).within(20, origin: @location).open
      end

  end

end

版本 1：

 module CategorizeJobs

  def self.fetch( location, category_name )
    c = Categorizer.new
    c.perform( location, category_name )
  end


  class Categorizer

    def perform( location, category_name )
      job_ids = get_correct_jobs(location, category_name)
      Category.includes(:jobs).where( jobs: { id:  job_ids } )
    end

    private

      def get_correct_jobs(location, category_name)
        jobs = filter_by_location(location)
        jobs = filter_by_category(jobs, category_name)

        jobs.collect(&:id)
      end

      def filter_by_category(jobs, category_name)
        return jobs unless category_name

        category = Category.where(name: category_name).first
        if category
          jobs = jobs.where(category: category)
        end

        jobs
      end

      def filter_by_location(location)
        if location
          jobs = get_jobs_at_location(location)
        else
          jobs = Job.open
        end
      end

      def get_jobs_at_location(location)
        Job.joins(:location).within(20, origin: location).open
      end

  end

end

Answer 1

有一个名为 Aldous 的 gem，可以帮助您在 Rails 应用程序中实现基于服务对象的架构。看看吧。

如果您在如何使用它和构建您的应用程序方面需要更多帮助，您可以查看this 和this 以获得更多帮助。