从另一个数组中的一个数组中查找元素并将总价格求和答案

【问题标题】：Find elements from one array in another one and Sum the Total Price从另一个数组中的一个数组中查找元素并将总价格求和
【发布时间】：2021-04-08 13:02:31
【问题描述】：

我正在尝试通过在“对象：价格”中查找礼物的价格来计算给定名称（在本例中为“彼得”）中“对象：礼物”中礼物数组的“总成本”。如果present 不在 Prices 数组中，价格为 0。

ie：在彼得的情况下，礼物的“总成本”是 1,001，而在 Dana 的情况下是 6,800。

结果将是一个价格数组，给定 2 个对象数组中的匹配礼物（即 peter = [1,1000]，因为他的礼物是“咖啡”和“假期”）所以稍后我计算总和里面有我的减速器功能。

我尝试通过过滤名称来获取数组，然后尝试查找包含的元素，但我的解决方案仅迭代第一个元素（咖啡）并返回一个未定义的数组。

关于为什么和如何前进的提示有什么想法吗？

我是一名初学者，非常感谢一些指导。

干杯，

const presents = [
  { "name": "peter", "presents": ["coffee", "holidays"], "present": "sock", "score": 10 },
  { "name": "dana", "presents": ["car", "phone"], "present": "sock", "score": 9.25 }
]

const prices = [{"present": "coffee","price": 1}, {"present": "holidays","price": 1000
  },{"present": "videogames","price": 40},{"present": "computer","price": 600},{"present": "tattoo","price": 30},{"present": "clothes","price": 80},{"present": "car","price": 6000},{"present": "phone","price": 800},{"present": "motorbike","price": 3500}]

const name = 'peter'
const presentsPrices = []
const filteredName = presents.filter((element)=>element.name===name?element:false).map((element, i)=> element.presents[i].includes(prices[i].present)? presentsPrices.push(prices[i].price):0)
const reducer = (accumulator, currentValue) => accumulator + currentValue;
const sum = presentsPrices.reduce(reducer)

console.log(sum)

【问题讨论】：

标签： javascript arrays object filter

【解决方案1】：

您可以使用.find 获取礼物的价格。此外，不需要.filter 和.map，因为您正在搜索一个对象，然后获取它的presents（如果存在）：

const presents = [
  { "name": "peter", "presents": ["coffee", "holidays"], "present": "sock", "score": 10 },
  { "name": "dana", "presents": ["car", "phone"], "present": "sock", "score": 9.25 }
];
const prices = [
  { "present": "coffee","price": 1 }, 
  { "present": "holidays","price": 1000 },
  { "present": "videogames","price": 40},
  { "present": "computer","price": 600 },   
  { "present": "tattoo","price": 30 },
  { "present": "clothes","price": 80 },
  { "present": "car","price": 6000},    
  { "present": "phone","price": 800 },
  { "present": "motorbike","price": 3500 }
];
const name = 'peter';

// get presents of person with this name
const { presents: filteredNamePresents = [] } = presents.find(element => element.name===name) || {};
console.log(`Presents: ${filteredNamePresents}`);

// get prices list of these presents
const presentsPrices = filteredNamePresents.reduce((acc,item) => {
  const { price } = prices.find(price => price.present===item) || {};
  acc = price ? [...acc, price] : acc;
  return acc;
}, []);
console.log(`Prices: ${presentsPrices}`);

// calculate totla sum of the prices
const sum = presentsPrices.reduce((accumulator, currentValue) => accumulator + currentValue);
console.log(`Sum: ${sum}`);

【讨论】：

【解决方案2】：

这里有一些东西可以帮助你的代码：

const people = {
  "peter": ["coffee", "holidays"],
  ...
};

const presents = {
  "coffee": 1,
  "holidays": 1000,
  ...
};

但除了使用 JSON 更好地组织之外，我真的无法帮助您解决问题。

【讨论】：