如何将字典单个键值添加在一起？答案

【问题标题】：How do I add dictionary individual key values together?如何将字典单个键值添加在一起？
【发布时间】：2021-03-14 10:59:54
【问题描述】：

我有一本字典，其中包含人员及其完成任务的持续时间。我也希望添加他们的个人时间。

office_time_dict = {
    "john": ["0:00:30", "0:02:04", "0:00:16"],
    "bryan": ["0:00:30", "0:02:04", "0:00:16"],
    "mike": ["0:00:30", "0:02:04", "0:00:16"],
}
total_time = 0

for k, v in office_time_dict.items():
    office = office_time_dict[k]
    for time in office:
        timeparts = [int(s) for s in time.split(":")]
        total_time += (timeparts[0] * 60 + timeparts[1]) * 60 + timeparts[2]
    total_time, sec = divmod(total_time, 60)
    hr, min = divmod(total_time, 60)
    print("%d:%02d:%02d" % (hr, min, sec))

当前输出：0:02:50、0:02:52、0:02:52

对我做错了什么感到困惑，因为 john、bryan 和 mike 的所有输出都应该是相同的，但是 bryan 和 mike 延迟了 2 秒

【问题讨论】：

您必须将“total_time”的值重置为零，每次循环 k,v。
这是出错的那一行：> 它保存了 [total_time] 变量中“2”的值，它传递给下一个循环犯了这个错误。

标签： python python-3.x dictionary time

【解决方案1】：

试试这个：

office_time_dict = {'john': ['0:00:30', '0:02:04','0:00:16'], 'bryan': ['0:00:30', 
                   '0:02:04','0:00:16'], 'mike' : ['0:00:30', '0:02:04','0:00:16']}

for person in office_time_dict:
    office = office_time_dict[person]
    total_time = 0 # re-initialise total_time for each person inside loop
    for time in office:
        timeparts = [int(s) for s in time.split(':')]
        total_time += (timeparts[0] * 60 + timeparts[1]) * 60 + timeparts[2]
    total_time, sec = divmod(total_time, 60)
    hr, min = divmod(total_time, 60)
    print('%d:%02d:%02d' % (hr, min, sec))

【讨论】：

【解决方案2】：

如果您将 HH:MM:SS-to-seconds（反之亦然）代码分解为它们自己的函数，您会过得更好：

# Convert a h:m:s string to seconds
def hms_to_sec(hms):
    h, m, s = [int(part, 10) for part in hms.split(":")]
    return h * 60 * 60 + m * 60 + s


# Convert seconds to h:m:s
def sec_to_hms(s):
    hm, s = divmod(s, 60)
    h, m = divmod(hm, 60)
    return "%02d:%02d:%02d" % (h, m, s)


# Source data (slightly modified from question so the guys have different times)
office_time_dict = {
    "john": ["0:00:30", "0:02:04", "0:00:16"],
    "bryan": ["0:00:20", "0:03:04", "0:00:16"],
    "mike": ["0:00:10", "0:04:04", "0:00:16"],
}

# Convert each person's time to seconds and sum up
total_times_sec = {
    person: sum(hms_to_sec(time) for time in times)
    for (person, times) in office_time_dict.items()
}

# Convert the summed seconds back to H:M:S
total_times_hms = {
    person: sec_to_hms(sec) for (person, sec) in total_times_sec.items()
}

# Sum the seconds and convert back to H:M:S
grand_total_hms = sec_to_hms(sum(total_times_sec.values()))

print(total_times_hms)
print(grand_total_hms)

打印出来

{'john': '00:02:50', 'bryan': '00:03:40', 'mike': '00:04:30'}
00:11:00

【讨论】：

【解决方案3】：

在主循环之前，变量 total_time 只初始化了一次：

total_time = 0

在主循环的每次迭代之后，total_time 的值不是0，而是2。
然后将该值添加到命令中

total_time += (timeparts[0] * 60 + timeparts[1]) * 60 + timeparts[2]

如何纠正：

将初始化移到主循环中：

for k, v in office_time_dict.items():
    total_time = 0

【讨论】：

【解决方案4】：

您只需将total_time 的初始化移动到循环内。您也可以使用 items() 方法返回的值，而不是通过键访问字典。

office_time_dict = {'john': ['0:00:30', '0:02:04','0:00:16'],
                    'bryan': ['0:00:30', '0:02:04','0:00:16'],
                    'mike' : ['0:00:30', '0:02:04','0:00:16']}
 
for k, v in office_time_dict.items():
    total_time = 0
    for time in v:
        timeparts = [int(s) for s in time.split(':')]
        total_time += (timeparts[0] * 60 + timeparts[1]) * 60 + timeparts[2]
    total_time, sec = divmod(total_time, 60)
    hr, minutes = divmod(total_time, 60)
    print('%d:%02d:%02d' % (hr, minutes, sec))

【讨论】：