Python CSV 查找平均耗时答案

【问题标题】：Python CSV Finding average time takenPython CSV 查找平均耗时
【发布时间】：2018-03-14 04:46:06
【问题描述】：

我试图找出平均花费的时间。值“x”将允许我获得每一行所花费的时间，但我如何能够找到所有行所花费的平均时间。我会认为它类似于 x 除以计数，但我无法找到解决方案......那里的任何专业人士都可以帮助我吗？？

import datetime,time,csv
from itertools import islice
from Tkinter import Tk      #python GUI programming
from tkFileDialog import askopenfilename
from collections import Counter
from datetime import datetime
import pandas


Tk().withdraw()
category_list=[]
description_list=[]
reported_date=[]
acknowledged_date=[]
count = 0

# hard code all possible date formats
date_formats = ['%m/%d/%Y %H:%M', '%-d-%b-%y', '%d/%m/%Y %h:%M %p', '%d/%m/%Y %H:%M', '%A, %d %B %Y %H:%M','%A, %d %B %Y %H:%M','%A %d %B %Y %H%M',"%d/%m/%Y %H:%M %p"," %d/%m/%Y %H:%M %p", '%d-%b-%y' ,
                   '%d.%m.%Y', '%d %b %Y %H%M hrs', '%d %b %Y %H%M', '%d-%m-%y', '%d-%b-%y', '%b-%d-%y', '%d-%a-%y','%e-%a-%y','%b %d %Y %H%M hrs','%d/%b/%Y %m:%M %p','%A, %e %B %Y %H:%M',' %d/%m/%Y %h:%M','%d-%b-%y','%m/%d/%Y  %H:%M:%S %p']
#file = askopenfilename() #ask user which file to open
#f = open(file,'r')
with open('Feedback and Complaints_Sample Dataset.csv', 'rb') as f:
    reader = csv.reader(f)
    header = next(reader) #read 2nd line onwards
    data= []  #make a list called data
    for row in reader: #assign data in every column and name them respectively


      for format in date_formats:
        try:

            reported_on = datetime.strptime(row[0], format) #try and get the dates
            acknowledged_on = datetime.strptime(row[12], format) #try and get the dates
            x= acknowledged_on-reported_on #time taken to acknowledge

            #acknowledged_date.append(acknowledged_on)
            #reported_date.append(reported_on)
            count += 1

            break # if correct format, dont test any other formats

        except ValueError:
            pass # if incorrect format, try other formats`enter code here`

【问题讨论】：

请编辑您的问题以包含 CSV 文件中的一些示例行，以及您期望它们的输出。

标签： python csv datetime time average

【解决方案1】：

减去两个datetime 对象会创建一个timedelta 对象。您需要保留总时间，因此创建一个 timedelta 对象，并将每个 x 添加到您的总时间中。

最后，您可以将您的total_time 除以您的count：

import csv
from itertools import islice
from datetime import datetime, timedelta


count = 0
total_time = timedelta()

# hard code all possible date formats
date_formats = ['%m/%d/%Y %H:%M', '%-d-%b-%y', '%d/%m/%Y %h:%M %p', '%d/%m/%Y %H:%M', '%A, %d %B %Y %H:%M','%A, %d %B %Y %H:%M','%A %d %B %Y %H%M',"%d/%m/%Y %H:%M %p"," %d/%m/%Y %H:%M %p", '%d-%b-%y' ,
                '%d.%m.%Y', '%d %b %Y %H%M hrs', '%d %b %Y %H%M', '%d-%m-%y', '%d-%b-%y', '%b-%d-%y', '%d-%a-%y','%e-%a-%y','%b %d %Y %H%M hrs','%d/%b/%Y %m:%M %p','%A, %e %B %Y %H:%M',' %d/%m/%Y %h:%M','%d-%b-%y','%m/%d/%Y  %H:%M:%S %p']

with open('Feedback and Complaints_Sample Dataset.csv', 'rb') as f:
    reader = csv.reader(f)
    header = next(reader) #read 2nd line onwards

    for row in reader:
        for format in date_formats:
            try:
                reported_on = datetime.strptime(row[0], format) #try and get the dates
                acknowledged_on = datetime.strptime(row[12], format) #try and get the dates
                x = acknowledged_on - reported_on #time taken to acknowledge
                total_time += x
                count += 1
                break # if correct format, don't test any other formats

            except ValueError:
                pass # if incorrect format, try other formats`enter code here`

print "Total time taken:", total_time                
print "Average time taken:", total_time / count

注意：date_formats 的逻辑意味着同一行中的两个日期将始终共享相同的日期格式。

【讨论】：