【发布时间】：2021-05-11 13:24:28
【问题描述】：
我能够使用来自 JSON 响应的改造在我的应用程序上显示一些天气数据，但当前时间 (dt)、日出和日落在我的文本视图上显示为秒，即 1612730263。 所以我需要将时间转换为实时格式（小时和分钟），例如晚上 9:30。 免责声明： Java: Date from unix timestamp 和 How to convert seconds to time format? 对我不起作用，因为我的响应来自 API。因此我的问题不是重复的。
我的 API 响应：
{
"lat":9.0765,
"lon":7.3986,
"timezone":"Africa/Lagos",
"timezone_offset":3600,
"current":{
"dt":1612779720,
"sunrise":1612763455,
"sunset":1612805901,
"temp":304.15,
"feels_like":302.14,
"pressure":1013,
"humidity":33,
"dew_point":286,
"uvi":8.42,
"clouds":42,
"visibility":7000,
"wind_speed":4.12,
"wind_deg":100,
"weather":[
{
"id":802,
"main":"Clouds",
"description":"scattered clouds",
"icon":"03d"
}
]
}
}
HomeActivity 中我的 Retrofit 调用：
Retrofit retrofit = new Retrofit.Builder().baseUrl(BaseUrl).addConverterFactory(GsonConverterFactory.create()).build();
WeatherService service = retrofit.create(WeatherService.class);
Call<WeatherResponse> call = service.getCurrentWeatherData(lat, lon, AppId);
call.enqueue(new Callback<WeatherResponse>() {
@Override
public void onResponse(@NonNull Call<WeatherResponse> call, @NonNull Response<WeatherResponse> response) {
if (response.code() == 200) {
WeatherResponse weatherResponse = response.body();
assert weatherResponse != null;
assert response.body() != null;
// current time textview
time_field.setText(String.valueOf(response.body().getCurrent().getDt()));
我在 FirstFragment 中的 Retrofit 调用：
Retrofit retrofit = new Retrofit.Builder().baseUrl(BaseUrl).addConverterFactory(GsonConverterFactory.create()).build();
WeatherService service = retrofit.create(WeatherService.class);
Call<WeatherResponse> call = service.getCurrentWeatherData(lat, lon, AppId);
call.enqueue(new Callback<WeatherResponse>() {
@Override
public void onResponse(@NonNull Call<WeatherResponse> call, @NonNull Response<WeatherResponse> response) {
if (response.code() == 200) {
WeatherResponse weatherResponse = response.body();
assert weatherResponse != null;
assert response.body() != null;
// sunrise & sunset time textviews
rise_time.setText(response.body().getCurrent().getSunrise() + " AM");
set_time.setText(response.body().getCurrent().getSunset() + " PM");
编辑
WeatherResponse.java：
public class WeatherResponse {
@SerializedName("lat")
@Expose
private Double lat;
@SerializedName("lon")
@Expose
private Double lon;
@SerializedName("timezone")
@Expose
private String timezone;
@SerializedName("timezone_offset")
@Expose
private Integer timezoneOffset;
@SerializedName("current")
@Expose
private Current current;
public Double getLat() {
return lat;
}
public void setLat(Double lat) {
this.lat = lat;
}
public Double getLon() {
return lon;
}
public void setLon(Double lon) {
this.lon = lon;
}
public String getTimezone() {
return timezone;
}
public void setTimezone(String timezone) {
this.timezone = timezone;
}
public Integer getTimezoneOffset() {
return timezoneOffset;
}
public void setTimezoneOffset(Integer timezoneOffset) {
this.timezoneOffset = timezoneOffset;
}
public Current getCurrent() {
return current;
}
public void setCurrent(Current current) {
this.current = current;
}
}
Current.java：
public class Current {
@SerializedName("dt")
@Expose
private Integer dt;
@SerializedName("sunrise")
@Expose
private Integer sunrise;
@SerializedName("sunset")
@Expose
private Integer sunset;
@SerializedName("temp")
@Expose
private Double temp;
@SerializedName("feels_like")
@Expose
private Double feelsLike;
@SerializedName("pressure")
@Expose
private Integer pressure;
@SerializedName("humidity")
@Expose
private Integer humidity;
@SerializedName("dew_point")
@Expose
private Double dewPoint;
@SerializedName("uvi")
@Expose
private Double uvi;
@SerializedName("clouds")
@Expose
private Integer clouds;
@SerializedName("visibility")
@Expose
private Integer visibility;
@SerializedName("wind_speed")
@Expose
private Double windSpeed;
@SerializedName("wind_deg")
@Expose
private Integer windDeg;
@SerializedName("weather")
@Expose
private List<Weather> weather = null;
public Integer getDt() {
return dt;
}
public void setDt(Integer dt) {
this.dt = dt;
}
public Integer getSunrise() {
return sunrise;
}
public void setSunrise(Integer sunrise) {
this.sunrise = sunrise;
}
public Integer getSunset() {
return sunset;
}
public void setSunset(Integer sunset) {
this.sunset = sunset;
}
public Double getTemp() {
return temp;
}
public void setTemp(Double temp) {
this.temp = temp;
}
public Double getFeelsLike() {
return feelsLike;
}
public void setFeelsLike(Double feelsLike) {
this.feelsLike = feelsLike;
}
public Integer getPressure() {
return pressure;
}
public void setPressure(Integer pressure) {
this.pressure = pressure;
}
public Integer getHumidity() {
return humidity;
}
public void setHumidity(Integer humidity) {
this.humidity = humidity;
}
public Double getDewPoint() {
return dewPoint;
}
public void setDewPoint(Double dewPoint) {
this.dewPoint = dewPoint;
}
public Double getUvi() {
return uvi;
}
public void setUvi(Double uvi) {
this.uvi = uvi;
}
public Integer getClouds() {
return clouds;
}
public void setClouds(Integer clouds) {
this.clouds = clouds;
}
public Integer getVisibility() {
return visibility;
}
public void setVisibility(Integer visibility) {
this.visibility = visibility;
}
public Double getWindSpeed() {
return windSpeed;
}
public void setWindSpeed(Double windSpeed) {
this.windSpeed = windSpeed;
}
public Integer getWindDeg() {
return windDeg;
}
public void setWindDeg(Integer windDeg) {
this.windDeg = windDeg;
}
public List<Weather> getWeather() {
return weather;
}
public void setWeather(List<Weather> weather) {
this.weather = weather;
}
}
我需要将提供的代码链接到我的应用程序，以便更容易实施。我有 dt 转换的基本知识，但不是来自天气 API 响应。我认为使用我的 textviews 来转换数据会更好（如果有任何方法可以使用我的 textviews 来做）
【问题讨论】：
-
您需要阅读您正在调用的 Web 服务的文档，以确定如何解释 JSON 中返回的值。时间值看起来像自 Unix 纪元以来的秒数。
-
我已经阅读了完整的文档openweathermap.org/api/one-call-api，没有说明如何解释这些值
-
您链接到的页面有一个“API 响应中的字段”部分，描述了如何解释响应中的值。
-
这正是我在改造中所称的领域。好吧，我想你说得有道理，数据以秒为单位显示，所以我需要将其实时转换为小时和分钟
-
这能回答你的问题吗？ Java: Date from unix timestamp
标签： java android api datetime retrofit